Answer:
E(X) = 6
Var(X) = 3.394
Step-by-step explanation:
Let X represent the number of carp caught out of the 20 fishes caught. Now, if we are to assume that each
of the (100, 20) ways to catch the 20 fishes will be equally likely.
Thus, we can say that X fulfills a hypergeometric
distribution with parameters as follows;
n = 20, N = 100, k = 30
Formula for expected mean value in hypergeometric distribution is;
E(X) = nk/N
E(X) = (20 × 30)/100
E(X) = 6
Formula for variance is;
Var(X) = (nk/N) × [((n - 1)(k - 1)/(N-1))) + (1 - nk/N)]
Var(X) = ((20 × 30)/100) × [((20 - 1)(30 - 1)/(100 - 1)) + (1 - (20 × 30/100)]
Var(X) = 6 × 0.5657
Var(X) = 3.394
I have no idea good question though 69=y
Answer:
x(t) = –5 + 6t; y(t) = 3 – 9t
Step-by-step explanation:
we need to find the probability of bad sound cards.
we are having 1000 computers so 1000 sound card will be there.
manager found that 4 sounds are defective out of 1000 sound cards.
of defective sound cards=
we know that 1 is the total probability.out of 0.004 is the failure.
