What are ratios of lengths of the longer leg of 30-60-90 triangle to the length of it hypotenuse

Use properties to find the sum or product 89+27+11

yulyashka [42]

The answer to 89+27+11 is 127

3 0

3 years ago

The corners of a meadow are shown on a coordinate grid. Ethan wants to fence the meadow. What length of fencing is required?

Nuetrik [128]

Answer:

34.6 units

Step-by-step explanation:

The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.

The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).

Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:

Distance between point A(-6, 2) and point B(2, 6):

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$A(-6, 2)) = (x_1, y_1)$

$B(2, 6) = (x_2, y_2)$

$AB = \sqrt{(2 - (-6))^2 + (6 - 2)^2}$

$AB = \sqrt{(8)^2 + (4)^2}$

$AB = \sqrt{64 + 16} = \sqrt{80}$

$AB = 8.9$ (nearest tenth)

Distance between B(2, 6) and C(7, 1):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$B(2, 6) = (x_1, y_1)$

$C(7, 1) = (x_2, y_2)$

$BC = \sqrt{(7 - 2)^2 + (1 - 6)^2}$

$BC = \sqrt{(5)^2 + (-5)^2}$

$BC = \sqrt{25 + 25} = \sqrt{50}$

$BC = 7.1$ (nearest tenth)

Distance between C(7, 1) and D(3, -5):

$CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$C(7, 1) = (x_1, y_1)$

$D(3, -5) = (x_2, y_2)$

$CD = \sqrt{(3 - 7)^2 + (-5 - 1)^2}$

$CD = \sqrt{(-4)^2 + (-6)^2}$

$CD = \sqrt{16 + 36} = \sqrt{52}$

$CD = 7.2$ (nearest tenth)

Distance between D(3, -5) and A(-6, 2):

$DA = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$D(3, -5) = (x_1, y_1)$

$A(-6, 2) = (x_2, y_2)$

$DA = \sqrt{(-6 - 3)^2 + (2 - (-5))^2}$

$DA = \sqrt{(-9)^2 + (7)^2}$

$DA = \sqrt{81 + 49} = \sqrt{130}$

$DA = 11.4$ (nearest tenth)

Length of fencing required = 8.9 + 7.1 + 7.2 + 11.4 = 34.6 units

8 0

2 years ago

A total of 259 tickets were sold to a benefit concert for a total of $5,312. Two types of tickets were sold: adult tickets were

jeyben [28]

Answer:

113

Step-by-step explanation:

Let the number of adult tickets sold =a

Let the number of student tickets sold =s

A total of 259 tickets were sold, therefore:

a+s=259

Adult tickets were sold for $24 each and student tickets were sold for $16 each.

Total Revenue = $5,312

Therefore:

24a+16s=5,312

We solve the two derived equations simultaneously.

From the first equation

a=259-s

Substitute a=259-s into 24a+16s=5,312

24(259-s)+16s=5,312

6216-24s+16s=5,312

-8s=5,312-6216

-8s=-904

Divide both sides by -8

s=113

Therefore, 113 student tickets were sold.

4 0

3 years ago

Which expression can be used to find the value of expression below -(7/10) + 2/8 + 1/10 - (4/8)

maks197457 [2]

Answer:

(-17)/20

Step-by-step explanation:

Simplify the following:

-7/10 + 2/8 + 1/10 - 4/8

The gcd of 2 and 8 is 2, so 2/8 = (2×1)/(2×4) = 2/2×1/4 = 1/4:

-7/10 + 1/4 + 1/10 - 4/8

The gcd of -4 and 8 is 4, so (-4)/8 = (4 (-1))/(4×2) = 4/4×(-1)/2 = (-1)/2:

-7/10 + 1/4 + 1/10 + -1/2

Put -7/10 + 1/4 + 1/10 - 1/2 over the common denominator 20. -7/10 + 1/4 + 1/10 - 1/2 = (2 (-7))/20 + 5/20 + 2/20 - 10/20:

(2 (-7))/20 + 5/20 + 2/20 - 10/20

2 (-7) = -14:

(-14)/20 + 5/20 + 2/20 - 10/20

-14/20 + 5/20 + 2/20 - 10/20 = (-14 + 5 + 2 - 10)/20:

(-14 + 5 + 2 - 10)/20

-14 + 5 + 2 - 10 = (5 + 2) - (14 + 10):

((5 + 2) - (14 + 10))/20

5 + 2 = 7:

(7 - (14 + 10))/20

| 1 | 4

+ | 1 | 0

| 2 | 4:

(7 - 24)/20

7 - 24 = -(24 - 7):

(-(24 - 7))/20

| 1 | 14

| 2 | 4

- | | 7

| 1 | 7:

Answer: (-17)/20

4 0

2 years ago

Helpppppppppppppppppp

schepotkina [342]

Answer: 4b+9

Step-by-step explanation: add the B's together

6 0

2 years ago

Read 2 more answers