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goldenfox [79]
3 years ago
7

4. Find Q1, Q2, Q3, IQR and the Range of this set of data.

Mathematics
1 answer:
galina1969 [7]3 years ago
6 0

Answer:

it is C. Q3- Q1 tell me if it was right or not

OR if it is for a listing order it would be this List in ascending order:-

32 39 45 48 50 57 65 68 70

Q1 = (39+45)/2 = 42

Q2 = 50

Q3 = (65+68)/2 = 66.5

Correct option is the first one if there are choices

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Consider the graph with four lines below. On a coordinate plane, line a has a positive slope and goes through points (negative 1
yan [13]

Answer:

The correct option is;

line a and line b

Step-by-step explanation:

Lina a passes through (-1, 0) and (1, 2)

Line b passes through (2, 2) and (-1, -1)

Line c passes through (0, 3) and (1, 0)

Line d passes through y = 1

An equation that has no solution

By examination, from the plot of the coordinates using an online tool, the system that would have no solution is the system of line a and line b because they are parallel lines and cannot meet or have a point where there is a common solution, therefore, there are no solutions when the equations of the two lines are combined in one equation

Slope of line a = -2/-2 = 1

Slope of line b = 3/3 = 1

The slopes of lines a and b are equal, therefore, line a and line b are parallel.

5 0
4 years ago
The rate at which an assembly line workers efficiency E (expressed as a percent) changes with respect to time t is given by E'(t
zavuch27 [327]

By the fundamental theorem of calculus,

E(t)=E(1)+\displaystyle\int_1^t E'(u)\,\mathrm du

So we have

E(t)=92+\displaystyle\int_1^t(75-6u)\,\mathrm du

E(t)=92+(75u-3u^2)\bigg|_1^t

E(t)=20 + 75 t - 3 t^2

4 0
3 years ago
A Air Freshener Used 3 3/4 milliliters perfume wanted to make 3 air freshners how many milliliters of perfume woud she use
larisa [96]
1 and a fourth because 3 3/4 devided by three equals 1 1/4
5 0
3 years ago
Find the lateral area for the prism. L.A. =<br> Find the total area for the prism. T.A. =
Ksivusya [100]
The lateral area of the prism is given by:
LA=[area of the two triangles]+[area of the lateral rectangles]
hypotenuse of the triangle will be given by Pythagorean:
c^2=a^2+b^2
c^2=6^2+4^2
c^2=52
c=sqrt52
c=7.211'
thus the lateral area will be:
L.A=2[1/2*4*6]+[6*8]+[8*7.211]
L.A=24+48+57.69
L.A=129.69 in^2

The total are will be given by:
T.A=L.A+base area
base area=length*width
=4*8
=32 in^2
thus;
T.A=32+129.69
T.A=161.69 in^2

6 0
3 years ago
Read 2 more answers
Hey Friends!! Wanna talk and chill?
Ivan

Answer:

say less

Step-by-step explanation:

8 0
3 years ago
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