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3 years ago

What polynomial must be added to x^2-2x+6 so that the sum is 3x^2+7x?

Mathematics

1 answer:

slavikrds [6]3 years ago

5 0

2x^2+9x-6 i found this by subtracting 3x^2+7x from the other equation

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Stan ran 4 7/10 miles, which was 1 3/10 fewer miles than Matt ran. Four students wrote and solved equations to find m, the numbe

nydimaria [60]

Answer: Miles ran by Matt = 6 miles

Step-by-step explanation: Miles ran by Stan = 4 7/10

i.e. 1 3/10 miles less than Matt.

∴ Miles ran by Matt = 4 7/10 + 1 3/10 = 60/10 = 6miles

∴ Miles ran by Matt = 6 miles

6 0

3 years ago

Read 2 more answers

10 quater to 12 dimes , to 16 nickels

Fittoniya [83]

10 quarters to 12 dimes, to 16 nickels
10(0.25) to 12(0.1), to 16(0.05)
2.5 to 1.2, to 0.8
2.083 to 0.8
1.6664

4 0

3 years ago

A sprinter who weighs 706 N runs the first 5.5 m of a race in 1.6 s, starting from rest and accelerating uniformly. What are the

zhenek [66]

Answer:

(a) Speed = 6.875 m/s

(b) Kinetic Energy = 1.70 kJ

Step-by-step explanation:

Given:

d = 5.5 m

t = 1.6 s

W = 706 N

Part (a)

Using the equation of motion with the assumption of zero initial speed:

$d = \frac{1}{2} ({v-0})t$

$5.5= \frac{1}{2} (1.6v)$

The speed of the sprinter then become:

$v = 6.875 m/s$

Part (b)

Convert the weight of the sprinter to mass:

$m = \frac{w}{g}$

$m = \frac{706}{9.8}$

$m = 72 kg$

KE (Kinetic Energy) can then be calculated as:

$KE = \frac{1}{2} mv^{2}$

$KE = \frac{1}{2} (72)(6.875)^{2}$

$KE = 1701.56 J = 1.70 kJ$

Part (c)

The change of the kinetic energy is equivalent to the work done by the sprinter. The average power P is the rate of the work done and can be calculated as

$P = \frac{KE}{t} \\\$

$P = \frac{1701.56}{1.6}$

$P = 1063.48 W = 1.06 kW$

5 0

3 years ago

The quotient of m and 7

pochemuha

The expression would me m / 7 or m and 7 as a fraction. M is on the top

6 0

3 years ago

A local country club has a membership of 600 and operates facilities that include an 18-hole championship golf course and 12 ten

shusha [124]

Answer:

0.45 = 45% probability that the member uses the golf course but not the tennis courts

Step-by-step explanation:

I am going to solve this question using the events as Venn sets.

I am going to say that:

Event A: Uses the golf courses.

Event B: Uses the tennis courts.

5% use neither of these facilities.

This means that $P(A \cup B) = 1 - 0.05 = 0.95$

75% use the golf course, 50% use the tennis courts

This means, respectively, by:

$P(A) = 0.75, P(B) = 0.5$

Probability that a member uses both:

This is $P(A \cap B)$ . We have that:

$P(A \cap B) = P(A) + P(B) - P(A \cup B)$

$P(A \cap B) = 0.75 + 0.5 - 0.95 = 0.3$

What is the probability that the member uses the golf course but not the tennis courts?

This is $P(A - B)$ , which is given by:

$P(A - B) = P(A) - P(A \cap B)$

$P(A - B) = 0.75 - 0.3 = 0.45$

0.45 = 45% probability that the member uses the golf course but not the tennis courts

3 0

3 years ago