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3 years ago

Determine which of the following logarithms is expanded correctly.

Mathematics

1 answer:

ziro4ka [17]3 years ago

7 0

Answer:

A) log(jk2y = 7log i + 2logk

Step-by-step explanation:

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A number is randomly selected from {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}. A is represented by the event that the number picked is grea

fomenos

P(A) = P(8) + P(9) + P(10) = 3/10 so P(A complement) = 1 - P(A) = 1 - 3/10 = 7/10 - D

7 0

3 years ago

Read 2 more answers

Rewrite the parametric equations by eliminating the parameter. Select ONE.

Vinil7 [7]

Answer:

$Y=(X-7)/2$

Step-by-step explanation:

we have

$X=2t+3$ -----> equation A

$Y=t-2$ -----> $t=Y+2$ -----> equation B

Substitute equation B in equation A

$X=2(Y+2)+3$

$X=2Y+4+3$

$X=2Y+7$

solve for Y

$2Y=X-7$

$Y=(X-7)/2$

6 0

2 years ago

Peter planted 5/12 of his garden with asparagus and 3/12 with beans.

UkoKoshka [18]

Answer: He has planted 2/3 and there is 1/3 left to plant.

Explanation: You need to add your fractions together, because each of those is a section of the garden and you need the total of how much of the garden he has planted.

This isn’t too difficult because the denominators are the same.

5/12 + 3/12 = 8/12

It is 8/12 because since the denominators are the same, you just need to add the numerators. Imagine you have a pie that’s cut into 12 pieces, and you and your friends take 5, and then your family takes 3. How many or gone now? 8 pieces. From how many pieces? 12 pieces. So 8/12 pieces are gone.

So Peter has planted 8/12 of his garden. This however, can be simplified, because both of those numbers divide by 4.

8/4 = 2
12/4 = 3

So 8 is now 2, and 12 is now 3.

This is now 2/3.

If there is 2/3 gone, you need to figure out how much is left to get you to 1.

In this instance, 1 can be rewritten as 3/3, because 3 divided by 3 is 1.

In order to get from 2/3 to 1, you need to add 1/3, one more third to the two thirds you already have.

This means Peter has 1/3 left to plant.

Hope this helps :)

7 0

3 years ago

<img src="https://tex.z-dn.net/?f=tan20%2B4sin20%3D%5Csqrt%7B3%7D" id="TexFormula1" title="tan20+4sin20=\sqrt{3}" alt="tan20+4si

zepelin [54]

tan( 20 ) + 4 Sin( 20 ) =

( Sin( 20 ) / Cos( 20 ) ) + 4 Sin( 20 ) =

Sin( 20 ) + 4 Sin( 20 ).Cos( 20 ) / Cos( 20 ) =

Sin( 20 ) + 2 × 2 Sin(20).Cos(20)/ Cos(20) =

Sin( 20 ) + 2 × Sin( 40 ) / Cos( 20 ) =

Sin( 20 ) + 2Sin( 40 ) / Cos( 20 ) =

Sin( 20 ) + 2Cos( 50 ) / Cos ( 20 ) =

Sin( 20 ) + 2Cos( 20 + 30 ) / Cos( 20 ) =

________________________________

2 × Cos( 30 + 20 ) =

2 × [ Cos(30).Cos(20) - Sin(30).Sin(20) ] =

2 × [ √3/2 × Cos(20) - 1/2 × Sin(20) ] =

√3 Cos(20) - Sin(20)

_________________________________

Sin( 20 ) + 2Cos ( 20 + 30 ) / Cos( 20 ) =

Sin( 20 ) + √3 Cos(20) - Sin(20) / Cos(20) =

Sin(20) - Sin(20) + √3 Cos(20) / Cos(20) =

0 + √3 Cos(20) / Cos(20) =

√3 Cos(20) / Cos(20) =

Cos(20) simplifies from the numerator and denominator of fraction

√3 × 1 / 1 =

√3

And we're done ....

5 0

2 years ago

In the partial sequence …, 987, N, 2584, 4181, …, each new term is the sum of the two previous terms. Find the whole number valu

Alina [70]

Answer: 2584

Step-by-step explanation:

We can find N with 2584 and 4181.

4181 - 2584

= 1597

We can also check our answer by adding 1597 and 987

1597 + 987

= 2584

5 0

2 years ago