Answer:
(4y + 1) • (2y + 1)
Step-by-step explanation:
Step 1 :
Equation at the end of step 1 :
(23y2 + 6y) + 1
Step 2 :
Trying to factor by splitting the middle term
2.1 Factoring 8y2+6y+1
The first term is, 8y2 its coefficient is 8 .
The middle term is, +6y its coefficient is 6 .
The last term, "the constant", is +1
Step-1 : Multiply the coefficient of the first term by the constant 8 • 1 = 8
Step-2 : Find two factors of 8 whose sum equals the coefficient of the middle term, which is 6 .
-8 + -1 = -9
-4 + -2 = -6
-2 + -4 = -6
-1 + -8 = -9
1 + 8 = 9
2 + 4 = 6 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, 2 and 4
8y2 + 2y + 4y + 1
Step-4 : Add up the first 2 terms, pulling out like factors :
2y • (4y+1)
Add up the last 2 terms, pulling out common factors :
1 • (4y+1)
Step-5 : Add up the four terms of step 4 :
(2y+1) • (4y+1)
Which is the desired factorization
Final result :
(4y + 1) • (2y + 1)
Processing ends successfully
plz mark me as brainliest :)
