Ask question

Ask question

All categories

3 years ago

5

If tan x = 1.731 then sin x =?

1 answer:

lbvjy [14]3 years ago

5 0

Answer:

0.866

Step-by-step explanation:

If tan x = 1.731 then sin x =

Given data

tan x = 1.731

x= tan^-1 (1.731)

x= 59.98°

x= 60° approx

Aso

sin x=??

substitute

sin 60°= 0.866

Hence the answer is 0.866

You might be interested in

Trisha has $100 to spend on presents for 4 friends. She wants to spend the same amount on each friend. Write and solve an inequa

yKpoI14uk [10]

Answer:

4x<=100

Step-by-step explanation:

she has 4 friends to spend the 100 dollars on because she wants to spend the same amount on each friend you can multiply 4x. you can't spend more than 100 but you can spend 100$ so it would be <=100

6 0

3 years ago

a story has a contest to guess the mass of 10000 peanuts. If a peanut has a mass of about 0.45 then what would be a reasonable g

mamaluj [8]

1000000 i think...................................................

7 0

3 years ago

Read 2 more answers

26*3/4=___*____=_______=

Lina20 [59]

Answer:

19 1/2

Step-by-step explanation:

26/1 * 3/4

78/4

19 1/2

3 0

4 years ago

3 days ago - Regan wants to know the probability that both pizza and apple crisp are

jonny [76]

Pppppppwwwwwgggssdfffffffffgfsdhcd

7 0

3 years ago

As part of their business promotional package, the Milwaukee Chamber of Commerce would like an estimate of the mean cost per mon

Morgarella [4.7K]

Answer:

a) $884-2.426\frac{50}{\sqrt{40}}=864.82$

$884+2.426\frac{50}{\sqrt{40}}=903.179$

So on this case the 98% confidence interval would be given by (864.82;903.179)

b) For this case the upper bound of the confidence interval is lower than 950 so we don't have a significant evidence to conclude that the true mean is 950 per month

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=884$ represent the sample mean

$\mu$ population mean (variable of interest)

s=50 represent the sample standard deviation

n=40 represent the sample size

Solution to the problem

Part a

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=40-1=39$

Since the Confidence is 0.98 or 98%, the value of $\alpha=0.02$ and $\alpha/2 =0.01$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.01,39)".And we see that $t_{\alpha/2}=2.426$

Now we have everything in order to replace into formula (1):

$884-2.426\frac{50}{\sqrt{40}}=864.82$

$884+2.426\frac{50}{\sqrt{40}}=903.179$

So on this case the 98% confidence interval would be given by (864.82;903.179)

Part b

For this case the upper bound of the confidence interval is lower than 950 so we don't have a significant evidence to conclude that the true mean is 950 per month

3 0

3 years ago