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solniwko [45]
3 years ago
11

19.86 - 4.94 please help i don’t u understand this

Mathematics
2 answers:
mote1985 [20]3 years ago
3 0

Answer:

14.92

Step-by-step explanation:

you basically add them. just like normal numbers but add the decimal point.

mestny [16]3 years ago
3 0

Answer:

14.92

You need to do like this:

19.86

-4.94

--------

14.92

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9/25

Step-by-step explanation:

find a number that both the top and bottom are divisible by,

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\frac{207 }{575} ÷23

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The weights of 1250 pumpkins are normally distributed with mean of 28 pounds and a standard deviation of 6 pounds. About how man
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kropot72 3 years ago
This can be solved by using a standard normal distribution table. The z-score for 34 pounds is 1, the reason being that 34 is one standard deviation above the mean of 28 pounds.
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3 years ago
Suppose a consumer group suspects that the proportion of households that have three cell phones NOT known to be 30%. A cell phon
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Answer:

We conclude that the actual percentage of households is equal to 30%.

Step-by-step explanation:

We are given that a consumer group suspects that the proportion of households that have three cell phones NOT known to be 30%.

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Let p = <u><em>proportion of households that have three cell phones NOT known.</em></u>

So, Null Hypothesis, H_0 : p = 30%      {means that the actual percentage of households is equal to 30%}

Alternate Hypothesis, H_A : p \neq 30%     {means that the actual percentage of households different from 30%}

The test statistics that would be used here <u>One-sample z-test for proportions;</u>

                                T.S. =  \frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of households having three cell phones = \frac{43}{150} = 0.29

           n = sample of households = 150

So, <u><em>the test statistics</em></u>  =  \frac{0.29-0.30}{\sqrt{\frac{0.30(1-0.30)}{150} } }  

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<u>Also, P-value of the test statistics is given by;</u>

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