n=2
8+8(8-n)=40+8n (distribute 8 through the parenthesis)
8+64-8n=40-8n (add the numbers)
<em>72-</em>8n=40+8n (move the variable to the left side and change its sign)
<em>72</em><em>-</em>8n+8n=40
-8n+8n=40<em>-72</em> (connect like terms)
-16n = -32 (divide both sides by -16)
<u><em>n=2</em></u>
(2x2x2)(2x2)
=2x2x2x2x2
=2x2x2x2x2
=32
Answer:
[2] x = -5y - 4
// Plug this in for variable x in equation [1]
[1] 2•(-5y-4) - 5y = 22
[1] - 15y = 30
// Solve equation [1] for the variable y
[1] 15y = - 30
[1] y = - 2
// By now we know this much :
x = -5y-4
y = -2
// Use the y value to solve for x
x = -5(-2)-4 = 6
Solution :
{x,y} = {6,-2}
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Terms and Topics
Linear Equations with Two Unknowns
Solving Linear Equations by Substitution
Related Links
Algebra - Linear Systems with Two Variables
Step-by-step explanation:
Answer:
45-13= 32
32/8= 4
she can buy 4 lbs ham
Step-by-step explanation:
Answer:
C. 18
Step-by-step explanation:
We can find the numbers of payments using following formula
PV = PMT(1- (1+r)^-n)/r
PVr / PMT = 1 - (1+r)^-n
Where
PV = present value = $1,100
PMT = monthly payments = $71.50
r = interest rate = 19.2% / 12 = 1.6%
n = numbers of month = ?
Placing values in the formula
(1+r)^-n = 1 - PVr /PMT
1.016^-n = 1-1100 x 0.016/71.50
1.016^-n = 0.753846154
-n x log 1.016 = log 0.753846154
n = - log 0.753846154 /log 1.016
n = 17.8
n = 18 payments
