First distribute the negative through the parenthesis on the left and the 2 on the right.
-5 -15y +1 = 14y -32 - y
Combine like terms on the right and left
-4 -15y = 13y -32
Now move the variables to one side and the constants to the other.
Subtract 13y from both sides
-4 -28y = -32
Add 4 to both sides
-28y = -28
Divide both sides by -28
y = 1
Answer:
Question 1. (2.2, -1.4)
Question 2. (1.33, 1)
Step-by-step explanation:
Equations for the given lines are
-----(1)
It is given that this line passes through two points (0, 2.5) and (2.2, 1.4).
------(2)
This equation passes through (0, -3) and (2.2, -1.4).
Now we have to find a common point through which these lines pass or solution of these equations.
From equations (1) and (2),
x =
x = 2.2
From equation (2),
y = -1.4
Therefore, solution of these equations is (2.2, -1.4).
Question 2.
The given equations are y = 1.5x - 1 and y = 1
From these equations,
1 = 1.5x - 1
1.5x = 2
x =
Therefore, the solution of the system of linear equations is (1.33, 1).
Answer:
-29x-5
Step-by-step explanation:
Use the distributive property 5(-5x - 1 ) so…
-25x - 5
-4x - 25x - 5
combine like terms: -29x - 5
so you’re answer is -29x - 5
i hope this helps :)
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