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Annette [7]
3 years ago
11

I need help on parallelograms.

Mathematics
2 answers:
Kazeer [188]3 years ago
8 0

y=15

5y-20=2y+25 move terms

5y-2y = 25+20 calculate like terms

3y=45 divide both sides by 3

Montano1993 [528]3 years ago
4 0

You would make the equation 5y-20=2y+25 and then solve

You would add both sides by 20

5y=2y+45

Then you would add both sides by -2y

3y=45

finally you will multiply both sides by 1/3 and get 15 as Y

y=15

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with partial derivatives (set equal to 0)

L_x=1+2\lambda x=0\implies x=-\dfrac1{2\lambda}
L_y=1+2\lambda y=0\implies y=-\dfrac1{2\lambda}
L_z=-1+2\lambda z=0\implies z=\dfrac1{2\lambda}
L_\lambda=x^2+y^2+z^2-81=0\implies x^2+y^2+z^2=81

Substituting the first three equations into the fourth allows us to solve for \lambda:

x^2+y^2+z^2=\dfrac1{4\lambda^2}+\dfrac1{4\lambda^2}+\dfrac1{4\lambda^2}=81\implies\lambda=\pm\dfrac1{6\sqrt3}

For each possible value of \lambda, we get two corresponding critical points at (\mp3\sqrt3,\mp3\sqrt3,\pm3\sqrt3).

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5 0
3 years ago
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zaharov [31]

Answer:

C

Step-by-step explanation:

1/4= 0.25

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3 years ago
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Step-by-step explanation:

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Given:

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