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prohojiy [21]
3 years ago
11

Find a polynomial function of degree 4 with − 2 as a zero of multiplicity 3 and 0 as a zero of multiplicity 1.

Mathematics
1 answer:
MArishka [77]3 years ago
3 0
Degree 4 means you'll have x^4 as your leading term. Multiplicity of 3 means you have the same factor 3 times. So if x = -2, then (x + 2) = 0, so (x + 2) is used 3 times. FOIL that out 3 times and you get x^3 + 6x^2 + 12x + 8. Now multiply by (x + 0) to get a 4th degree polynomial of x^4 + 6x^3 + 12x^2 + 8x. There!
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alexandr402 [8]

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Step-by-step explanation:

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Fittoniya [83]

Answer:

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yuradex [85]

Given:

The function is

f(x)=\dfrac{4x}{x^2-16}

To find:

The asymptotes and zero of the function.

Solution:

We have,

f(x)=\dfrac{4x}{x^2-16}

For zeroes, f(x)=0.

\dfrac{4x}{x^2-16}=0

4x=0

x=0

Therefore, zero of the function is 0.

For vertical asymptote equate the denominator of the function equal to 0.

x^2-16=0

x^2=16

Taking square root on both sides, we get

x=\pm \sqrt{16}

x=\pm 4

So, vertical asymptotes are x=-4 and x=4.

Since degree of denominator is greater than degree of numerator, therefore, the horizontal asymptote is y=0.

8 0
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melisa1 [442]

Answer:

C) x = 9

Step-by-step explanation:

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