Question

Abigail is raising money for a school trip by selling bags of chips and packs of cookies. The price of each bag of chips is $1.50 and the price of each pack of cookies is $1.25. Yesterday Abigail made $27 from selling a total of 20 bags of chips and packs of cookies. Determine the number of bags of chips sold and the number of packs of cookies sold

Answer 1

The number of bags of chips sold is 8 and the number of packs of cookies sold is 12

Solution:

Let "a" be the number of bags of chips sold

Let "b" be the number of packs of cookies sold

Given that,

Cost of one bag of chips = $ 1.50

Cost of one pack of cookies = $ 1.25

Yesterday Abigail made $27 from selling a total of 20 bags of chips and packs of cookies

So we can frame a equation as:

Number of bags of chips sold + number of packs of cookies sold = 20

a + b = 20 ---- eqn 1

Also given that Abigail made $27 from selling

number of bags of chips sold x Cost of one bag of chips + number of packs of cookies sold x Cost of one pack of cookies = $ 27

$a \times 1.50 + b \times 1.25 = 27$

1.5a + 1.25b = 27 ---- eqn 2

Let us solve eqn 1 and eqn 2 to find values of "a" and "b"

From eqn 1,

a = 20 - b ---- eqn 3

Substitute eqn 3 in eqn 2

1.5(20 - b) + 1.25b = 27

30 - 1.5b + 1.25b = 27

-0.25b = -3

b = 12

Therefore from eqn 3,

a = 20 - b = 20 - 12 = 8

a = 8

Thus we have:

number of bags of chips sold = 8

number of packs of cookies sold = 12