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lorasvet [3.4K]
3 years ago
5

there are 3 digit numbers that are each divisible by 7 and by 8 without a remainder in each case. what is the largest of these 3

digit numbers?
Mathematics
1 answer:
densk [106]3 years ago
8 0
To be divisible by both 7 and 8 a number must be a multiple of 56.

Multiples of 56 are just 56n.  We wish to know the largest of three digit numbers that is a multiple of 56 then. So:

56n<1000

n<1000/56

n<17.86  and since n must be an integer n=17

Then the largest three digit multiple of 56 is:

56(17)=952
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