Answer:
usable capacity = 10 GB
Number of cylinders = 256
Block size = 4 KB
(1)Bytes in each cylinder = (10*230)/(256) = (10*222) = 40 MegaBytes
(2)Number of Blocks in each cylinder = (10*222)/(212) = 10K
(3)capacity of one track = 40 MegaBytes/(10*2) = 2 MB
Rotation speed = 3840 RPM
Number of rotations per second = 3840/60 = 64
Transfer rate = (2*64) = 128 MB/sec
Explanation:
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<span>Processor, Main Memory, I/O Modules, System Bus</span>
