For this case, we have the following expression:
We simplify the expression:
If we add similar terms, taking into account that different signs are subtracted and the sign of the greater one is placed, we have that 
So, we have to:
Answer:
-3x + x + 5 = -2x + 5
Answer:
54
Step-by-step explanation:
8(11 - 3) - 2(4 + 1)
11 - 3 = 8
4 + 1 = 5
8(5) - 2(5)
8 * 5 = 64
2 * 5 = 10
64 - 10 = 54
Answer:
When we have 3 numbers, like:
a, b and c.
Such that:
a < b < c.
These numbers are a Pythagorean triplet if the sum of the squares of the two smaller numbers, is equal to the square of the larger number:
a^2 + b^2 = c^2
This is equivalent to the Pythagorean Theorem, where the sum of the squares of the cathetus is equal to the hypotenuse squared.
Now that we know this, we can check if the given sets are Pythagorean triples.
1) 3, 4, 5
Here we must have that:
3^2 + 4^2 = 5^2
solving the left side we get:
3^2 + 4^2 = 9 + 16 = 25
and the right side:
5^2 = 25
Then we have the same in both sides, this means that these are Pythagorean triples.
2) 8, 15, 17
We must have that:
8^2 + 15^2 = 17^2
Solving the left side we have:
8^2 + 15^2 = 64 + 225 = 289
And in the right side we have:
17^2 = 17*17 = 289
So again, we have the same result in both sides, which means that these numbers are Pythagorean triples
Answer:
3, -8
(x is equal to 3 and y is equal to -8)
Step-by-step explanation:
<u>The system:</u>
{ 7x=-67-11y
{ 5x=-73-11y
<u>Finding a value for x:</u>
7x=-67-11y -> x = 
- 
<u>Solving for y by plugging in our x:</u>
[Equation] 5x = -73 -11y
[Plug-in] 5( - ) = -73 -11y
[Distribute the 5] 
- 
= -73 -11y
[Multiply by 7] 7 ( - ) = (-73 -11y) 7
[Simplify] -335 - 55y = -511 - 77y
[Add 335 and 77y to both sides] 22y = -176
[Divide by 22] y = -8
<u>Plug in our y to solve for x:</u>
5x = -73 -11y
5x = -73 -11(-8)
5x = -73 + 88
5x = 15
x = 3
Have a nice day!
I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)
- Heather
