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Lelu [443]
3 years ago
6

Which numbers are irrational​

Mathematics
2 answers:
shusha [124]3 years ago
8 0

Answer:

Pi

Step-by-step explanation:

Rzqust [24]3 years ago
3 0

Answer:

Hello there!

You didn't really give a list of numbers, but I got a photo that may help you!

Step-by-step explanation:

hope this helps!

(Maybe next time, for a smarter answer, you could add a list of numbers we could choose by) :)

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Pls help me right now ​
Irina-Kira [14]
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6 0
3 years ago
Find the area of a rectangle whose length is 8 and breath is 3<br>​
natulia [17]
Answer:
Area is 24

Explanation: times the length by the breath (width)
7 0
3 years ago
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Nataly_w [17]
Phytagorean Theorem i think
3 0
3 years ago
Read 2 more answers
Of the population of all fruit flies we wish to give a 90% confidence interval for the fraction which possess a gene which gives
maks197457 [2]

Answer:

The margin of error for the 90% confidence interval is of 0.038.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

To this end we have obtained a random sample of 400 fruit flies. We find that 280 of the flies in the sample possess the gene.

This means that n = 400, \pi = \frac{280}{400} = 0.7

90% confidence level

So \alpha = 0.1, z is the value of Z that has a pvalue of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

Give the margin of error for the 90% confidence interval.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

M = 1.645\sqrt{\frac{0.7*0.3}{400}}

M = 0.038

The margin of error for the 90% confidence interval is of 0.038.

8 0
3 years ago
C=2(y-k) solve for y​
marshall27 [118]

Answer:

\blue{y = \dfrac{C + 2k}{2}}

Step-by-step explanation:

C = 2(y - k)

C = 2y - 2k

C + 2k = 2y

\dfrac{C + 2k}{2} = y

y = \dfrac{C + 2k}{2}

5 0
2 years ago
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