Answer:
k = ⅕
Step-by-step explanation:
The slope-intercept equation for a straight line is
y = mx + b, where
m = the slope and
b = the y-intercept
Data:
(3,4) = a point on the line
(3k,0) = x-intercept
(0,-5k) = y-intercept
Calculations:
1. Slope
m = (y₂ - y₁)/(x₂ - x₁) = (-5k - 0)/(0 - 3k) = -5/(-3) = ⁵/₃
This makes the equation
y = ⁵/₃x - 5k
2. k
Insert the value of the known point: (3,4)
4 = (⁵/₃)(3) - 5k
4 = 5 - 5k
-1 = -5k
k = ⅕
The figure below shows your graph passing through (3,4) with intercepts 3k and -5k on the x- and y-axes respectively
.
They will see each other every 30 days but won't every 15 days
Step One
======
Find the length of FO (see below)
All of the triangles are equilateral triangles. Label the center as O
FO = FE = sqrt(5) + sqrt(2)
Step Two
======
Drop a perpendicular bisector from O to the midpoint of FE. Label the midpoint as J. Find OJ
Sure the Pythagorean Theorem. Remember that OJ is a perpendicular bisector.
FO^2 = FJ^2 + OJ^2
FO = sqrt(5) + sqrt(2)
FJ = 1/2 [(sqrt(5) + sqrt(2)] \
OJ = ??
[Sqrt(5) + sqrt(2)]^2 = [1/2(sqrt(5) + sqrt(2) ] ^2 + OJ^2
5 + 2 + 2*sqrt(10) = [1/4 (5 + 2 + 2*sqrt(10) + OJ^2
7 + 2sqrt(10) = 1/4 (7 + 2sqrt(10)) + OJ^2 Multiply through by 4
28 + 8* sqrt(10) = 7 + 2sqrt(10) + 4 OJ^2 Subtract 7 + 2sqrt From both sides
21 + 6 sqrt(10) = 4OJ^2 Divide both sides by 4
21/4 + 6/4* sqrt(10) = OJ^2
21/4 + 3/2 * sqrt(10) = OJ^2 Take the square root of both sides.
sqrt OJ^2 = sqrt(21/4 + 3/2 sqrt(10) )
OJ = sqrt(21/4 + 3/2 sqrt(10) )
Step three
find h
h = 2 * OJ
h = 2* sqrt(21/4 + 3/2 sqrt(10) ) <<<<<< answer.
Answer:
Step-by-step explanation:
100=100 and if it is asking if it is true than yes it is
Answer: 90
Step-by-step explanation:
