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bija089 [108]
3 years ago
15

Ross weighs 30 packets of sweets and finds the total mass is 1.5kg. He also weighs 25 chocolate bars and finds the mass is 1kg.

What is the difference in mass between a box of packet of sweets and a chocolate bar?
Mathematics
1 answer:
Step2247 [10]3 years ago
7 0
The answer to the question is 1.45 molucles and 3 duchea
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For which of the following equations are x = 5 and x = –5 both solutions?
Minchanka [31]
Short Answer B
Argument
A
A will give you x = +/- 5i 
x^2 + 25 = 0
x^2 = - 25       Take the square root.
sqrt(x^2) = +/- sqrt(-25)
x = +/- (5)i which is a complex number.


B
Is the answer
x^2 = 25
sqrt(x)^2 = sqrt(25)
x = +/- 5

C
Can't be factored just by looking at it. You can show that C is not true just by putting 5 into the equation
f(x) = x^2 + 10x - 25
f(5) = 25 + 10*5 - 25
f(5) = 50
C is not true.

D
D can be eliminated as C was
f(x) = x^2 - 5x - 25
f(5) = -25 ( l'll let you show this is not true). 5 is not a solution because it does not make f(x) = 0
6 0
4 years ago
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52 = p - 3<br> what is p ?
adelina 88 [10]

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Step-by-step explanation:

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52+3= p+3

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7 0
3 years ago
Hey, someone mind helping me w/ this?
kkurt [141]

Answer:

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mars1129 [50]

We have to select all of the transformations that could change the location of the asymptotes of a cosecant of secant function.

So given function can be written as:

y=csc( sec(x))

First we need to determine the location of asymptote which is basically a line that seems to be touching the graph of function at infinity.

From attached graph we see that Asymptotes (Green lines) are vertical.

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only Left or right side movement will change the position of vertical asymptote. Which is possible in Phase shift and period change.

Hence Phase shift and Period change are the correct choices.


8 0
4 years ago
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Oksanka [162]

0.09,0.032,0,5,0.44,0.48

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