Solve the remaining sides of the triangle:
C=95(degrees), a=1/2, and b=1/3
2 answers:
There is only 1 remaining side
We have 2 sides and an included angle, we use the Law of Cosines to solve the third side:
c^2 = a^2 + b^2 -2ab *cos(C)
c^2 = .5^2 + .333333333...^2 - 2 * .5 * .3333333... * cos (95)
c^2 = .25 + .1111111111111111... -2*.5*.3333333333...* -0.087156
c^2 = 0.3611111111 + 0.029052
c^2 = 0.3901631111
c = 0.6246303796
There is only 1 remaining side
We have 2 sides and an included angle, we use the Law of Cosines to solve the third side:
c^2 = a^2 + b^2 -2ab *cos(C)
c^2 = .5^2 + .333333333...^2 - 2 * .5 * .3333333... * cos (95)
c^2 = .25 + .1111111111111111... -2*.5*.3333333333...* -0.087156
c^2 = 0.3611111111 + 0.029052
c^2 = 0.3901631111
c = 0.6246303796
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