Question

Solve the remaining sides of the triangle: C=95(degrees), a=1/2, and b=1/3

Answer 1

There is only 1 remaining side

We have 2 sides and an included angle, we use the Law of Cosines to solve the third side:

c^2 = a^2 + b^2 -2ab *cos(C)

c^2 = .5^2 + .333333333...^2 - 2 * .5 * .3333333... * cos (95)

c^2 = .25 + .1111111111111111... -2*.5*.3333333333...* -0.087156

c^2 = 0.3611111111 + 0.029052

c^2 = 0.3901631111

c = 0.6246303796

Answer 2

There is only 1 remaining side

We have 2 sides and an included angle, we use the Law of Cosines to solve the third side:

c^2 = a^2 + b^2 -2ab *cos(C)

c^2 = .5^2 + .333333333...^2 - 2 * .5 * .3333333... * cos (95)

c^2 = .25 + .1111111111111111... -2*.5*.3333333333...* -0.087156

c^2 = 0.3611111111 + 0.029052

c^2 = 0.3901631111

c = 0.6246303796