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3 years ago

13

I have no clue how to do this!!!

1 answer:

adell [148]3 years ago

7 0

We can use trigonometric formulas to solve this question. Let's use cosine, since we can use the adjacent side and hypotenuse and solve for the hypotenuse:

We need to convert degrees to radians via the equation: $1degree= \frac{ \pi }{180}$

So 20 degrees converted to radians is: $20* \frac{ \pi }{180}= \frac{ \pi }{9}=0.349$

So now we use the equation:

$cos(0.349)= \frac{35}{y}$

$y= \frac{35}{cos(0.349)}$

$y=37.25$

So the length of the hypotenuse is 37.25.

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Margie's car can go 32 miles on a gallon of gas, and gas currently cost $4 per gallon. how many miles can Margie drive on $20 wo

Marysya12 [62]

To do this first we will divide the amount of dollars (20) by the amount of dollars 1 gallon is for (4). Then we will multiply the amount of times 4 goes into 20 by 32 and the answer will be the amount of miles she can drive worth $20.

20 ÷ 4 = 3
3 × 32 = 96

So, Margie can drive 96 miles in $20.

Hope I helped ya!! xD

6 0

3 years ago

PLZZZ HELPPPP MEEEEE PLS

zaharov [31]

Answer:

negative; -1/4

Step-by-step explanation:

5 0

4 years ago

Natalie bought 9 CDs to add to her collection.

GalinKa [24]

Answer:

36 i think

Step-by-step explanation:

she lost half and she has 18 so multiply 18 by 2 u will get 36

4 0

3 years ago

Find the area of each parallelogram. What is the relationship between the areas?

castortr0y [4]

Answer:

Area of parallelogram is given by:

$A = bh$

where b is the base and h is the height of parallelogram.

In parallelogram TQRS.

Coordinate of TQRS are;

T(8, 16), Q(4, 4), R(16, 4) and S(20, 16)

Coordinate of T'Q'R'S' are;

T'(2, 4), Q'(1, 1), R'(4, 1) and S'(5, 4)

Find the length of QR and PT:

Using distance(D) formula:

$D = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

$QR = \sqrt{(4-16)^2+(4-4)^2} =\sqrt{(-12)^2+0}= \sqrt{144}= 12$ units

Similarly;

For PT:

From the graph:

P(8, 4) and T(8, 16), then

$PT = \sqrt{(8-8)^2+(4-16)^2} =\sqrt{(-0)^2+(-12)^2}= \sqrt{144}= 12$ units

In parallelogram TQRS

PT represents the height and QR represents the base of the parallelogram respectively.

then;

Area of parallelogram TQRS = $QR \cdot PT$

⇒Area of parallelogram TQRS = $12 \cdot 12 = 144$ unit square.

Now, in parallelogram T'Q'R'S'

Q'R' represents the base and P'T' represents the height of the parallelogram respectively.

here, P'(2, 1)

Find the length of Q'R' and P'T':

$Q'R' = \sqrt{(1-4)^2+(1-1)^2} =\sqrt{(-3)^2+0}= \sqrt{9}= 3$ units

$P'T' = \sqrt{(2-2)^2+(1-4)^2} =\sqrt{(-0)^2+(-3)^2}= \sqrt{9}= 3$ units

Then;

Area of parallelogram T'Q'R'S' = $Q'R' \cdot P'T'$

Area of parallelogram T'Q'R'S' = $9 \cdot 9= 81$ unit square.

Now, we have to find the relationship between the areas.

$\frac{\text{Area of parallelogram TQRS}}{\text{Area of parallelogram T'Q'R'S'}} = \frac{144}{81}$

then;

the relationship between the areas of TQRS and T'Q'R'S' is:

$\text{Area of parallelogram TQRS} = \frac{144}{81} \cdot {\text{Area of parallelogram T'Q'R'S'}$

7 0

3 years ago

What is the equation of the line that is perpendicular to line a and passes through (2,7).

Aleonysh [2.5K]

Answer:

y = x + 5

Step-by-step explanation:

Slope = - 1

Slope of the perpendicular line = 1

Point (2,7)

(b) y-intercept= 7 - (1)(2)

= 5

7 0

3 years ago