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Ivenika [448]
2 years ago
7

Margie's car can go 32 miles on a gallon of gas, and gas currently cost $4 per gallon. how many miles can Margie drive on $20 wo

rth a gallon
Mathematics
1 answer:
Marysya12 [62]2 years ago
6 0
To do this first we will divide the amount of dollars (20) by the amount of dollars 1 gallon is for (4). Then we will multiply the amount of times 4 goes into 20 by 32 and the answer will be the amount of miles she can drive worth $20. 

20 ÷ 4 = 3
3 × 32 = 96

So, Margie can drive 96 miles in $20. 

Hope I helped ya!! xD 
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The average amount parents and children spent per child on back-to-school clothes in Autumn 2010 was $527. Assume the standard d
Ad libitum [116K]

Answer: a. 0.14085

b. 3.826 x 10^{-3}

c.  0.5437

d. 0.0811  

Step-by-step explanation:

Given average amount parents and children spent per child on back-to-school clothes in Autumn 2010 , \mu = $527

Given standard deviation , \sigma = $160

Let X = amount spent on a randomly selected child

Also Z = \frac{X-\mu}{\sigma}

a. Probability(X>$700) = P(\frac{X-\mu}{\sigma} > \frac{700-527}{160}) = P(Z>1.08125) = 0.14085 {Using Z % table}

b. P(X<100) = P( Z < \frac{100-527}{160}) = P(Z< -2.66875) = P(Z > 2.66875) = 3.826 x 10^{-3}

c. P(450<X<700) = P(X<700) - P(X<=450)

   P(X<700) = 1 - P(X>=700) = 1 - 0.14085 = 0.8592

   P(X<=450) = P(Z<= \frac{450-527}{160}) = P(Z<= -0.48125) = P(Z<=0.48125) = 0.3155

   So final   P(450<X<700) =  0.8592 - 0.3155 = 0.5437

d. P(X<=300) = P(Z<= \frac{300-527}{160}) = P(Z<= -1.4188) = P(Z>=1.4188) = 0.0811                                                                        

All the above probabilities are calculated using Z % table along with interpolation between two values.

7 0
3 years ago
I need Serious help here!
marishachu [46]

Answer:

Step-by-step explanation:

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7 0
2 years ago
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The quotient of a number and -3 is at most 7
Grace [21]

Answer:

-21

Step-by-step explanation:

-3 * 7

5 0
3 years ago
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For tax purposes, a car rental company assumes each car in their fleet depreciates by 6% per year. If the initial value of a car
n200080 [17]

The value of a car after 10 years be $20898.27 if the car rental company assumes each car in their fleet depreciates by 6% per year option (a) $20898.27 is correct.

<h3>What is an exponential function?</h3>

It is defined as the function that rapidly increases and the value of the exponential function is always a positive. It denotes with exponent \rm y = a^x

where a is a constant and a>1

We can solve this problem by exponential function:

The word  depreciate means the price is decreasing.

We can find the value be when the car is 10 years old:

p = 38800(1 - 0.06)¹⁰

p = 38800(0.94)¹⁰

p = 20898.266 ≈ $20898.27

Thus, the value of a car after 10 years be $20898.27 if the car rental company assumes each car in their fleet depreciates by 6% per year option (a) $20898.27 is correct.

Learn more about the exponential function here:

brainly.com/question/11487261

#SPJ1

6 0
1 year ago
What is the equation of the line that passes through the point (-1, -3) and has a slope of 3?
iogann1982 [59]

Answer:

y=3x

Step-by-step explanation:

Use a calculator to guess and check

5 0
3 years ago
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