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Ivenika [448]
3 years ago
7

Margie's car can go 32 miles on a gallon of gas, and gas currently cost $4 per gallon. how many miles can Margie drive on $20 wo

rth a gallon
Mathematics
1 answer:
Marysya12 [62]3 years ago
6 0
To do this first we will divide the amount of dollars (20) by the amount of dollars 1 gallon is for (4). Then we will multiply the amount of times 4 goes into 20 by 32 and the answer will be the amount of miles she can drive worth $20. 

20 ÷ 4 = 3
3 × 32 = 96

So, Margie can drive 96 miles in $20. 

Hope I helped ya!! xD 
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erastovalidia [21]

Answer:

See explanation.

General Formulas and Concepts:

<u>Algebra I</u>

  • Terms/Coefficients
  • Factoring

<u>Algebra II</u>

  • Polynomial Long Division

<u>Pre-Calculus</u>

  • Parametrics

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Derivative Property [Multiplied Constant]:                                                           \displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)

Derivative Property [Addition/Subtraction]:                                                         \displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Derivative Rule [Quotient Rule]:                                                                           \displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}

Parametric Differentiation:                                                                                     \displaystyle \frac{dy}{dx} = \frac{\frac{dy}{dt}}{\frac{dx}{dt}}

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle x = 2t - \frac{1}{t}

\displaystyle y = t + \frac{4}{t}

<u>Step 2: Find Derivative</u>

  1. [<em>x</em>] Differentiate [Basic Power Rule and Quotient Rule]:                             \displaystyle \frac{dx}{dt} = 2 + \frac{1}{t^2}
  2. [<em>y</em>] Differentiate [Basic Power Rule and Quotient Rule]:                             \displaystyle \frac{dy}{dt} = 1 - \frac{4}{t^2}
  3. Substitute in variables [Parametric Derivative]:                                           \displaystyle \frac{dy}{dx} = \frac{1 - \frac{4}{t^2}}{2 + \frac{1}{t^2}}
  4. [Parametric Derivative] Simplify:                                                                   \displaystyle \frac{dy}{dx} = \frac{t^2 - 4}{2t^2 + 1}
  5. [Parametric Derivative] Polynomial Long Division:                                     \displaystyle \frac{dy}{dx} = \frac{1}{2} - \frac{7}{2(2t^2 - 1)}
  6. [Parametric Derivative] Factor:                                                                   \displaystyle \frac{dy}{dx} = \frac{1}{2} \bigg( 1 - \frac{9}{2t^2 + 1} \bigg)

Here we see that if we increase our values for <em>t</em>, our derivative would get closer and closer to 0.5 but never actually reaching it. Another way to approach it is to take the limit of the derivative as t approaches to infinity. Hence  \displaystyle \frac{dy}{dx} < \frac{1}{2}.

Topic: AP Calculus BC (Calculus I + II)

Unit: Parametrics

Book: College Calculus 10e

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If Johnny can paint 1/2 of a wall in 1/4 of
kodGreya [7K]

Answer:

He can paint 2 walls in an hour and it will take him a 1/2 hour to paint one wall.

Step-by-step explanation:

Trust me I know.

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zhuklara [117]

i tried ;w;

Step-by-step explanation:

m(−11+m)=0

Step 1: Simplify both sides of the equation.

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Step 2: Factor left side of equation.

m(m−11)=0

Step 3: Set factors equal to 0.

m=0 or m−11=0

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Answer:

m=0 or m=11

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OLga [1]

Answer:

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barxatty [35]

Answer:

With the information provided, we have to assume it was Rob, in the order Rob, Henry, Charles, Dale.

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