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Veseljchak [2.6K]
3 years ago
7

Complete the table shown below. f(x) = 2x2 - 8x + 6 1 0 2 y 3 4. 6 X= y = Z ​

Mathematics
1 answer:
Serga [27]3 years ago
4 0

Answer:

x = 6, y = -2, z = 0

Step-by-step explanation:

To find x, we have to plug 0 into f(x). Therefore, x = f(0) = 2 * 0² - 8 * 0 + 6 = 6. Similarly, to find y, we have to plug 2 into f(x) so y = f(2) = 2 * 2² - 8 * 2 + 6 = -2. Finally, z = f(3) = 2 * 3² - 8 * 3 + 6 = 0.

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Sadie simplified the expression √54a^7b^3, where a>=0, as shown: √54a^7b^3= √3^2•6•a^2•a^5•b^2•b=3ab √6a^5b
Tamiku [17]

Answer:

We are to find the error made by Sadie and then find the correct simplification.

The error Sadie made is that she wrote a^7 as a^2 * a^5 instead of a^6 * a.

The square root of a^6 is a^3 and so she could have further simplified.

The correct simplification is shown below:

\sqrt{54a^7b^3} = \sqrt{2 * 3 * 3 * 3 * a^6 * a * b^2 * b} \\  \\= \sqrt{3^2 * a^6 * b^2 * 6 * a * b} \\\\= 3a^3b\sqrt{6ab}

4 0
3 years ago
Brayden has a triangular flag hanging in his room. What is the area of the flag? *
elena-s [515]

Answer:

if you want the base and the height you have to give me number or do you want the formula ?

3 0
2 years ago
Can you answer this question ?
Elden [556K]

Answer:

k = -14

Step-by-step explanation:

We should cross-multiply

9/(k -  7)  =  6 / k

9*k  = 6 * (k - 7)

9k = 6k  - 42

9k - 6k = -42

3k = -42

k = -14

7 0
3 years ago
-36y=x^2 The directrix of the parabola is:
Aleksandr-060686 [28]
Here, the equation of parabola is: (-36y)=x^2
The standard form of parabola is:

(X-h)^2=4p(y-k).
According to given equation, vertex = (0,0) and p = -9
This a vertical parabola opening down, because p = -9 here.
Therefore ditectrix will be y= -9
6 0
3 years ago
Given: AE ≅ CE ; DE ≅ BE Prove: ABCD is a parallelogram. Parallelogram A B C D is shown. Diagonals are drawn from point A to poi
nikklg [1K]

Answer:

The proof is below

Step-by-step explanation:

Given a parallelogram ABCD. Diagonals AC and BD intersect at E. We have to prove that AE is congruent to CE and BE is congruent to DE i.e diagonals of a parallelogram bisect each other.

In ΔACD and ΔBEC

AD=BC              (∵Opposite sides of a parallelogram are equal)

∠DAC=∠BCE       (∵Alternate angles)

∠ADC=∠CBE        (∵Alternate angles)

By ASA rule, ΔACD≅ΔBEC

By CPCT(Corresponding Parts of Congruent triangles)

AE=EC and DE=EB

Hence, AE is conruent to CE and BE is congruent to DE

6 0
3 years ago
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