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3 years ago

15

PLEASE ANSWERRRRRRRRR

1 answer:

Vikki [24]3 years ago

8 0

Answer: 4/5

Step-by-step explanation:

The slope : rise over run, or the change in y/ change in x

Change in y = 40 (50 - 90)

Change in x = 50 (50 - 100)

40/50 or 4/5

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Deloise has $1.20 in pennies and nickels in a jar on her desk. The number of pennies is three times the number of nickels. How m

irga5000 [103]

Answer: 45 Pennies and 15 Nickels

Step-by-step explanation:

0.05 x 15 = 0.75

0.01 x 45 = 0.45

0.45 + 0.75 = 1.20

7 0

3 years ago

Select all correct answers

Luden [163]

<h2>Answer = </h2><h2> $= \frac{1}{y {}^{5} x {}^{2} }$ </h2>

Step-by-step explanation:

Greetings !

simplify for variable y first

apply exponent rule

$a {}^{b} .a {}^{c} = a {}^{b +c \\ } \\ y {}^{ - 8}y {}^{5} = y {}^{ - 8 + 3}$

Add/subtract the numbers -8+3=5

$= y {}^{5}$

Apply exponent rule

$a {}^{ - b} = \frac{1}{a {}^{b} }$

Thus,

$y {}^{ - 5} = \frac{1}{y {}^{5} }$

secondly, simplify for the variable x

Apply exponent rule as we made on y

$x {}^{ - 2}$

$x {}^{ - 2} = \frac{1}{x {}^{2} }$

multiply bot the values we get

Hope it helps!

5 0

1 year ago

What do i point on the graph ?

ehidna [41]

Answer:

so there is a y and a x axis the x axis is on the bottem and the y axis is on the left

8 0

3 years ago

Venus and Serena measured a tennis court and found that it was 42ft longer than it was wide and had a perimeter of 228ft. What w

mr_godi [17]

Answer:

length = 78 feet

width = 36 feet

Step-by-step explanation:

Using one variable and an expression, you can set up an equation equal to the perimeter to find the measure of each side:

width = 'w'

length = '42ft longer than it was wide' = w + 42

The general formula for the perimeter of a rectangle:

P = 2w + 2l

Plugging in the given values and variables:

228 = 2w + 2(w + 42)

Distribute: 228 = 2w + 2w + 84

Combine like terms: 144 = 4w

Divide and solve: 36 = w

w = 36 ft

l = 36 + 42 = 78 ft

8 0

3 years ago

Express f(x) = |x-2| +|x+2| in the non-modulus form. Hence, sketch the graph of f.

alexgriva [62]

Recall that

$|x|=\begin{cases}x&\text{if }x\ge0\\-x&\text{if }x$

There are three cases to consider:

(1) When $x+2$ , we have $|x+2|=-(x+2)$ and $|x-2|=-(x-2)$ , so

$|x-2|+|x+2|=-(x-2)-(x+2)=-2x-4$

(2) When $x+2\ge0$ and $x-2$ , we get $|x+2|=x+2$ and $|x-2|=-(x-2)$ , so

$|x-2|+|x+2|=-(x-2)+(x+2)=4$

(3) When $x-2\ge0$ , we have $|x+2|=x+2$ and $|x-2|=x-2$ , so

$|x-2|+|x+2|=(x-2)+(x+2)=2x$

So

$|x-2|+|x+2|=\begin{cases}-2x-4&\text{if }x$

4 0

3 years ago