All categories

3 years ago

PLEASE ANSWERRRRRRRRR

Mathematics

1 answer:

Vikki [24]3 years ago

8 0

Answer: 4/5

Step-by-step explanation:

The slope : rise over run, or the change in y/ change in x

Change in y = 40 (50 - 90)

Change in x = 50 (50 - 100)

40/50 or 4/5

You might be interested in

Liz deposited money into an account in which interest is compounded quarterly at a rate of 3.2%. How much did she deposit if the

Anna [14]

Answer:

$4125.00

14.94 years

$379.50

Step-by-step explanation:

1. A = P(1 + r/n)^(nt)

4837.65 = P(1 + 0.032/4)^(4×5)

4837.65 = P(1.008)^(20)

P = 4125.00

2. A = P(1 + r/n)^(nt)

10250 = 5125(1 + 0.0475/1)^(1×t)

10250 = 5125(1.0475)^t

2 = 1.0475^t

ln 2 = t ln 1.0475

t = 14.94

3. Beth pays the first $100, bringing the cost to $1118. She then pays 25% of this, which is $279.50. So she pays a total of $379.50.

5 0

3 years ago

Help pls, will mark brainliest

BaLLatris [955]

Here , we are provided with a table which shows 5 consecutive terms of an arithmetic sequence . But before solving further , let's recall that ;

The n'th term of a Arithmetic Sequence let's say it be ${\sf T_n}$ is given by ;

${\boxed{\bf T_{n}=T_{1}+(n-1)d}}$

Where , d is the common difference

Now , here we are given with ;

${\quad \qquad \sf \blacktriangleright \blacktriangleright \blacktriangleright T_{1}=8 \: and \: T_{5}=-4}$

We have to find the 2nd , 3rd and 4th term respectively ,

Now , by using the above formula , 5th term can be written as ;

${: \implies \quad \sf T_{1}+(5-1)d=T_{5}}$

Putting the values and transposing 1st term to RHS , we have ;

${: \implies \quad \sf 4d = -4-8}$

${: \implies \quad \sf d=-\dfrac{12}{4}}$

${: \implies \quad \sf d=-3}$

Now , as we got the common difference , so we can find out the missing terms now ;

${: \implies \quad \sf T_{2}= T_{1}+(2-1)d}$

${: \implies \quad \sf T_{2}= 8 +d}$

${: \implies \quad \sf T_{2}= 8-3}$

${: \implies \quad \bf \therefore \: T_{2}= 5}$

Now

${: \implies \quad \sf T_{3}= T_{1}+(3-1)d}$

${: \implies \quad \sf T_{3}= 8 +2d}$

${: \implies \quad \sf T_{3}= 8-6}$

${: \implies \quad \bf \therefore \: T_{3}= 2}$

Also ,

${: \implies \quad \sf T_{4}= T_{1}+(4-1)d}$

${: \implies \quad \sf T_{4}= 8 +3d}$

${: \implies \quad \sf T_{4}= 8-9}$

${: \implies \quad \bf \therefore \: T_{4}= -1}$

Now , The given table can be written as ;

${\begin{array}{|c|c|c|c|c|c|}\cline{1-6} \bf n & \sf 1 & 2 & 3 & 4 & 5 \\ \cline{1-6} \bf T_{n} & \sf 8 & 5 & 2 & -1 & -4 \end{array}}$

Note :- Kindly view the answer from web , if you're not able to see the full answer from here ;

brainly.com/question/26750175

8 0

2 years ago

What is the value of when x = 16 and y = 2? 32 02 2 2 4 Hi

nasty-shy [4]

If you are multiplying 16 times 2 then 32 would be your answer. If you are subtracted your answer would be 14. If you are adding them your answer would be 18. I don’t really see what sign is being used.

7 0

3 years ago

These tables of values represent functions. In which table do the values represent and exponential function?

deff fn [24]

D since the other options increase at a constant rate. For A, each increase in x is +4. For B, each increase in x is +1. For C, each increase is 13

6 0

3 years ago

PLEASE HELP ME IS DUE TMR

IrinaVladis [17]

Answer:

p = 8000 + 2(6000)

20000

Step-by-step explanation:

Given that:

Profit in 1988 = 6000

Profit in 2003 = 8000 more Than double the profit made in 1998

Hence profit in 2003 (p) can be expressed as :

p = 8000 + 2(6000)

Hence profit in 2003

p = 8000 + 12000

p = 20,000

6 0

3 years ago