Question

What is the equation of the line perpendicular to y=2x+3.14 going through the points (2,4)?

Answer 1

Answer:

$x+2y-10=0$

Step-by-step explanation:

Consider an equation: $y=mx+c$

Here, m is the slope of the line and c is the y-intercept.

Given equation is $y=2x+3.14$

Here, slope is $m=2$

As product of slopes of two perpendicular lines is equal to $-1$, slope of the required line is $m_1=\frac{-1}{m}=\frac{-1}{2}$.

Let $(x_1,y_1)=(2,4)$

Equation of the required line is $y-y_1=m_1(x-x_1)$

$y-4=\frac{-1}{2}(x-2)\\2(y-4)=-1(x-2)\\2y-8=-x+2\\x+2y-8-2=0\\x+2y-10=0$