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larisa86 [58]
3 years ago
6

Need help on this question please

Mathematics
2 answers:
lianna [129]3 years ago
7 0
The lines are perpendicular.

Hope I can help you!

aliina [53]3 years ago
4 0

Answer:

lines are perpendicular

Step-by-step explanation:

The equation of a vertical line parallel to the y- axis is

x = c

Where c is the value of the x- coordinates the line passes through

x = - 1 ← is the equation of a vertical line

The equation of a horizontal line parallel to the x- axis is

y = c

Where c is the value of the y- coordinates the line passes through

y = - 1 ← is a horizontal line

Since lines are vertical and horizontal they are perpendicular to each other.

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Can constants in linear combinations be bigger than 1
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It can be as big as 1-2.
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3 years ago
How do I do this question? Please Help!
AURORKA [14]

Answer:

2x+50 and 5x-55 both are congruent or have same measure.

Step-by-step explanation:

Since we want to prove that both lines are parallel, this means no theorems that involve with parallel lines apply here.

First of, we know that AC is a straight line and has a measure as 180° via straight angle.

x+25 and 2x+50 are supplementary which means they both add up to 180°.

Sum of two measures form a straight line which has 180°.

Therefore:-

x+25+2x+50=180

Combine like terms:-

3x+75=180

Subtract 75 both sides:-

3x+75-75=180-75

3x=105

Divide both sides by 3.

x=35°

Thus, x = 35°

Then we substitute x = 35 in every angles/measures.

x+25 = 35°+25° = 60°

2x+50 = 2(35°)+50° = 70°+50° = 120°

5x-55 = 5(35°)-55 = 175°-55° = 120°

Since 2x+50 and 5x-55 have same measure or are congruent, this proves that both lines are parallel.

5 0
3 years ago
Read 2 more answers
500,000,000,000 in scientific notation
Alex Ar [27]
500,000,000,000 in scientific notation:
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Solve x2 – 12x + 59 = 0 for x.
lesya692 [45]
No real solutions. x2−[email protected]−12x+59=0x2−12x+59=0Step 1: Use quadratic formula with a=1, b=-12, c=59.x=−b±√b2−4ac2ax=−(−12)±√(−12)2−4(1)(59)2(1)x=12±√−922
3 0
3 years ago
=<br> If f(x) = x + 1, and g(x) = 2x,<br> then<br> f(g(x)) = [ ? ]x + [ ]<br> =
hodyreva [135]

Answer:

[2]x + [1]

Step-by-step explanation:

f(g(x)) = f(2x) = 2x + 1

so f(g(x) = [2]x + [1]

6 0
2 years ago
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