Answer:
84cm^2
Step-by-step explanation:
P=2l+2w
We are given,
P=40cm
l=2w+2
Plug these into the first formula and solve for the dimensions,
length and width, of the rectangle:
40=2(2w+2)+2w Simplify
40=4w+4+2w
40=6w+4
36=6w
6=w OR the width is 6cm, therefore,
the length is
l=2(6)+2
l=14cm
To calculate the area of a rectangle, A=lw,
plug the length,14cm, and the width, 6cm, into this formula
A=(14)(6)
A=84cm2 OR the area of the rectangle is 84cm^2
Question:
Solution:
Let the following equation:
![\sqrt[]{12-x}=\text{ x}](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B12-x%7D%3D%5Ctext%7B%20x%7D)
this is equivalent to:
![(\sqrt[]{12-x})^2=x^2](https://tex.z-dn.net/?f=%28%5Csqrt%5B%5D%7B12-x%7D%29%5E2%3Dx%5E2)
this is equivalent to:
this is equivalent to:
thus, we can conclude that
x= 3.
Answer:
28
Step-by-step explanation:
which is 28.07 degree
x= 23.99
23.99+4=h=28
Answer:
see explanation
Step-by-step explanation:
given the 2 equations
y = x² - 2x - 19 → (1)
y + 4x = 5 → (2)
substitute y = x² - 2x - 19 into (2)
x² - 2x - 19 + 4x = 5 ( subtract 5 from both sides )
x² + 2x - 24 = 0 ← in standard form
(x + 6)(x - 4) = 0 ← in factored form
equate each factor to zero and solve for x
x + 6 = 0 ⇒ x = - 6
x - 4 = 0 ⇒ x = 4
substitute each value of x into (1) for corresponding y- coordinate
x = - 6 : y = (- 6)² - 2(- 6) - 19 = 36 + 12 - 19 = 29 ⇒ (- 6, 29)
x = 4 : y = 4² - 2(4) - 19 = 16 - 8 - 19 = - 11 ⇒ (4, - 11)
the solutions are (- 6, 29), (4, - 11)
I hope this helps you
x'=1 y'=4 slope = -3
slope. (x'-x)=y'-y
-3. (1-x)=4-y
-3+3x=4-y
y=4+3-3x
y=7-3x
