Answer:
C. ![y=\frac{4}{5}x+7](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B4%7D%7B5%7Dx%2B7)
Step-by-step explanation:
Alan and his classmates found that the line of best fit through the data had the equation ![y=-\frac{5}{4}x+18](https://tex.z-dn.net/?f=y%3D-%5Cfrac%7B5%7D%7B4%7Dx%2B18)
The slope of this line is ![m=-\frac{5}{4}](https://tex.z-dn.net/?f=m%3D-%5Cfrac%7B5%7D%7B4%7D)
If a line would intersect this line of best fit at right angles, then the two lines are perpendicular to each other.
The slopes of perpendicular lines are negative reciprocals of each other,
Hence that line must have slope ![\frac{-1}{-\frac{5}{4}} =\frac{4}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B-1%7D%7B-%5Cfrac%7B5%7D%7B4%7D%7D%20%3D%5Cfrac%7B4%7D%7B5%7D)
Therefore we look for a line whose slope is
from the given options.
That line is the third option ![y=\frac{4}{5}x+7](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B4%7D%7B5%7Dx%2B7)
The frustum can be considered as consisting of a square pyramid, less the
cut volume.
- The mass of the stand, is approximately 18.60905 kg
Reasons:
The given parameter of the frustum are;
The density of the frustum, ρ = 85 g/cm³
Height of pyramid, h = 9 cm
Side length of base = 10 cm
Height of frustum
By proportional shapes, the side length of the top of the frustum can be found as follows;
![\dfrac{4 \, cm}{9 \, cm} = \dfrac{x}{10 \, cm}](https://tex.z-dn.net/?f=%5Cdfrac%7B4%20%5C%2C%20cm%7D%7B9%20%5C%2C%20cm%7D%20%3D%20%5Cdfrac%7Bx%7D%7B10%20%5C%2C%20cm%7D)
![x = \dfrac{4 \, cm}{9 \, cm} \times 10 \, cm = 4\frac{4}{9} \, cm](https://tex.z-dn.net/?f=x%20%3D%20%5Cdfrac%7B4%20%5C%2C%20cm%7D%7B9%20%5C%2C%20cm%7D%20%5Ctimes%2010%20%5C%2C%20cm%20%3D%204%5Cfrac%7B4%7D%7B9%7D%20%5C%2C%20cm)
![V = \dfrac{h}{3} \times \left(B_1 + B_2 + \sqrt{B_1 \times B_2} \right)](https://tex.z-dn.net/?f=V%20%3D%20%5Cdfrac%7Bh%7D%7B3%7D%20%5Ctimes%20%5Cleft%28B_1%20%2B%20B_2%20%2B%20%5Csqrt%7BB_1%20%5Ctimes%20B_2%7D%20%5Cright%29)
B₁ = 10², B₂ = ![\left(4\frac{4}{9} \right)^2](https://tex.z-dn.net/?f=%5Cleft%284%5Cfrac%7B4%7D%7B9%7D%20%5Cright%29%5E2)
Therefore;
![V = \dfrac{4}{3} \times \left(10^2 + \left(4\frac{4}{9} \right)^2 + \sqrt{10^2 \times \left(4\frac{4}{9} \right)^2} \right) \approx 218.93](https://tex.z-dn.net/?f=V%20%3D%20%5Cdfrac%7B4%7D%7B3%7D%20%5Ctimes%20%5Cleft%2810%5E2%20%2B%20%5Cleft%284%5Cfrac%7B4%7D%7B9%7D%20%20%5Cright%29%5E2%20%20%2B%20%5Csqrt%7B10%5E2%20%5Ctimes%20%20%5Cleft%284%5Cfrac%7B4%7D%7B9%7D%20%20%5Cright%29%5E2%7D%20%5Cright%29%20%5Capprox%20218.93)
The volume of the stand, V ≈ 218.93 cm³
Mass = Volume × Density
∴ Mass of the stand, m = 218.93 cm³ × 85 g/cm³ = 18,609.05 grams = 18.60905 kg.
Learn more here:
brainly.com/question/24323975
Let garret’s age be x
x + 2 + (x + 3) + 2 = 39
2x + 7 = 39
2x = 32
x = 32/2
x = 16
Garrett’s age after two years = 16 + 2 = 18
Step-by-step explanation:
Statement | Reason
CB=AB Given
DBC=DBA Given
DB = DB Reflexive Property
/_\ DBC
=~
/_\DBA SAS
Sorry for the formatting the =~ means congruent.
Answer:
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pass=7neBw6