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3 years ago

12

PLEASE HELP!

2 answers:

vaieri [72.5K]3 years ago

7 0

The graph is not given , but with the help of information provided by you in the question:

X : 0 1 2 3 4 5 →→ Time in Seconds

Y : 0 25 50 75 100 125 →→Height of Elevator Above Ground in feet

Rate of change can be found by using two point slope form of line.

The slope of line joining two points $(x_{1},y_{1}) and (x_{2},y_{2})$ is given by = $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Taking two points (1,25) and (2,50) and finding the slope of line, that is Rate of change:

Rate of change = $\frac{50-25}{2-1}=25$

Option (B) 25 is correct answer.

Westkost [7]3 years ago

5 0

Hello!

We know that the rate of change is just like speed as in the last Q so....

usually the rate of change is y/x so in this case, The Correct Answer is 100%

Option B "25".

I Hope my answer has come to your Help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead! :)

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joja [24]

$\huge\text{Hey there!}$

$\huge\textbf{Equation:}$

$\mathbf{1 \dfrac{1}{5} \times \dfrac{x}{3} = \dfrac{9}{10}}$

$\huge\textbf{Solve:}$

$\mathbf{1 \dfrac{1}{5} \times \dfrac{x}{3} = \dfrac{9}{10}}$

$\mathbf{\rightarrow \dfrac{1\times5+1}{5} \times \dfrac{x}{3} = \dfrac{9}{10}}$

$\mathbf{\rightarrow \dfrac{5 + 1}{5} \times \dfrac{x}{3} = \dfrac{9}{10}}$

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$\huge\textbf{Simplify it:}$

$\mathbf{\rightarrow \dfrac{2}{5}x = \dfrac{9}{10}}$

$\huge\textbf{Multiply \boxed{\bf \dfrac{5}{2}} to both sides:}$

$\mathbf{\rightarrow \dfrac{5}{2}\times \dfrac{2}{5}x = \dfrac{5}{2}\times \dfrac{9}{10}}$

$\huge\textbf{Simplify it:}$

$\mathbf{\rightarrow x = \dfrac{5}{2}\times \dfrac{9}{10}}$

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$\mathbf{\rightarrow x = \dfrac{45\div5}{20\div5}}$

$\mathbf{\rightarrow x = \dfrac{9}{4}}$

$\mathbf{x \approx 2 \dfrac{1}{4}}$

$\huge\textbf{Therefore, your answer should be:}$

$\huge\boxed{\mathsf{x = }\frak{2 \dfrac{1}{4}}}\huge\checkmark$

$\huge\text{Good luck on your assignment \& enjoy your day!}$

~ $\frak{Amphitrite1040:)}$

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