Question

Make x the subject of these equations. Thank you! ^^

Answer 1

Answer:

$y = \frac{x}{x - 2} \\ y(x - 2) = x \\ xy- 2y = x \\ xy - x = 2y \\ x(y - 1) = 2y \\ x = \frac{2y}{(y - 1)}$

$y = \frac{(x + 4)}{(x - 9)} \\ y(x - 9) = (x + 4) \\ xy- 9y = x + 4 \\ xy - x = 9y + 4 \\ x(y - 1) = 9y + 4 \\ x = \frac{9y + 4}{(y - 1)}$

$y = \frac{(a - 5x)}{(bx + 8)} \\ y(bx + 8) = (a - 5x) \\ ybx + 8y = (a - 5x) \\ ybx + 5x = a - 8y \\ x(yb + 5) = a - 8y \\ x = \frac{(a - 8y)}{(yb + 5)}$

$y = \frac{6x - 8}{3x - 13} \\ y(3x - 13) = 6x - 8 \\ 3xy - 13y = 6x - 8 \\ 3xy - 6x = 13y - 8 \\ x(3y - 6) = 13y - 8 \\ x = \frac{13y - 8}{(3y - 6)}$

sorry I don't know how to do the last one.