Question

Geometry question confused on how to solve this answer

Answer 1

The acute angles of a right triangle are complementary, so $\boxed{m\angle F=34^{\circ}}$.

Using right-angle trigonometry, we know that

$\cos 56^{\circ}=\frac{26}{DF}\\\\DF=\frac{26}{\cos 56^{\circ}}\\\\\boxed{DF \approx 46.5}$

$\tan 56^{\circ}=\frac{FE}{26}\\\\FE=26 \tan 56^{\circ}\\\\\boxed{FE \approx 38.5}$