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3 years ago

I need help please and thank you

Mathematics

1 answer:

Vladimir79 [104]3 years ago

3 0

Answer: B. Sons of liberty

Step-by-step explanation:

The sons of liberty were a secret organization formed in the thirteen colonies to oppose the British government and further the development of the colonies.

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1.A cube has side lengths of 15 inches, what is the surface area and volume of the cube? 2. A cube has side lengths of 8 inches,

omeli [17]

Answer:

Cube 1: 3375 cubed inches, 1350 inches squared.

Cube 2: 512 cubed inches, 384 inches squared.

Step-by-step explanation:

Formula for Volume of a Cube: $V=s^3\\$ (s - side length)

Formula for Surface Area of a Cube: $SA=6s^2$ (s- side length)

The side length's 15 inches.

Find the volume:

$V=15^3\\\rightarrow 15*15*15=3375\\\boxed {V=3375}$

The volume of cube one is 3375in³.

Find the surface area:

$SA=6(15)^2\\\rightarrow 15^2 = 225\\SA = 6 * 225\\\boxed {SA=1350}$

The surface area of cube 1 is 1350in².

The side length's 8 inches.

Find the volume:

$V=8^3\\\rightarrow 8*8*8= 512\\\boxed {V=512}$

The volume of cube two is 512in³.

Find the surface area:

$SA=6(8)^2\\\rightarrow 8^2=64\\SA=6*64\\\boxed {SA=384}$

The surface area of cube 2 is 384in².

<em>Brainilest Appreciated. </em>

3 0

3 years ago

Solve each system of linear equations by substitution.

Naddik [55]

$3x-2(2x-7)=9 \\ 3x-4x+14=9 \\ -x+14=9 \\ -14\ \ \ \ -14 \\ -x=-5 \\ /-1/-1 \\ \ \ x=5$

3 0

2 years ago

Read 2 more answers

Evaluate the surface integral:S

rjkz [21]

Assuming $S$ does not include the plane $z=0$ , we can parameterize the region in spherical coordinates using

$\mathbf r(u,v)=\left\langle3\cos u\sin v,3\sin u\sin v,3\cos v\right\rangle$

where $0\le u\le2\pi$ and $0\le v\le\dfrac\pi/2$ . We then have

$x^2+y^2=9\cos^2u\sin^2v+9\sin^2u\sin^2v=9\sin^2v$
$(x^2+y^2)=9\sin^2v(3\cos v)=27\sin^2v\cos v$

Then the surface integral is equivalent to

$\displaystyle\iint_S(x^2+y^2)z\,\mathrm dS=27\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^2v\cos v\left\|\frac{\partial\mathbf r(u,v)}{\partial u}\times \frac{\partial\mathbf r(u,v)}{\partial u}\right\|\,\mathrm dv\,\mathrm du$

We have

$\dfrac{\partial\mathbf r(u,v)}{\partial u}=\langle-3\sin u\sin v,3\cos u\sin v,0\rangle$
$\dfrac{\partial\mathbf r(u,v)}{\partial v}=\langle3\cos u\cos v,3\sin u\cos v,-3\sin v\rangle$
$\implies\dfrac{\partial\mathbf r(u,v)}{\partial u}\times\dfrac{\partial\mathbf r(u,v)}{\partial v}=\langle-9\cos u\sin^2v,-9\sin u\sin^2v,-9\cos v\sin v\rangle$
$\implies\left\|\dfrac{\partial\mathbf r(u,v)}{\partial u}\times\dfrac{\partial\mathbf r(u,v)}{\partial v}\|=9\sin v$

So the surface integral is equivalent to

$\displaystyle243\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv\,\mathrm du$
$=\displaystyle486\pi\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv$
$=\displaystyle486\pi\int_{w=0}^{w=1}w^3\,\mathrm dw$

where $w=\sin v\implies\mathrm dw=\cos v\,\mathrm dv$ .

$=\dfrac{243}2\pi w^4\bigg|_{w=0}^{w=1}$
$=\dfrac{243}2\pi$

4 0

3 years ago

What is the circumference of a circle if the area is 7.2

maw [93]

~45.25 because the formula for circumference is 2(3.14286)a or 2(3.14286)7.2

8 0

3 years ago

Find the area of the trapezoid. points are (-5,-3)(4,-3)(6,-7)(-7,-7)

Olegator [25]

Answer:

44 square units

Step-by-step explanation:

The area of a trapezoid with bases b₁ and b₂ and height h is given by the formula

$A=\left(\dfrac{b_1+b_2}{2}\right)h$

If you're wondering how we get this formula, check the attached illustration (remember the area of a parallelogram is its base multiplied by its height)! Moving on to our trapezoid, the pairs of points (-5,-3)(4,-3) and (6,-7)(-7,-7) form two horizontal segments, which form b₁ and b₂, and our height is the distance between the y-coordinates -3 and -7, which is 4. We can find b₁ and b₂ by finding the distance between the x coordinates in their pairs of points:

$b_1=|-5-4|=|-9|=9\\b_2=|6-(-7)|=|6+7|=13$

Putting it altogether:

$A=\left(\dfrac{9+13}{2}\right)(4)=\left(\dfrac{22}{2}\right)(4)=(11)(4)=44$

So the area of our trapezoid is 44.

4 0

3 years ago