Answer:
<h3>Q cuts the diagonal PA into 2 equal halves, since the diagonals of rhombus meet at right angles.</h3><h3>The value of x is 8.</h3>
Step-by-step explanation:
Given that Quadrilateral CAMP below is a rhombus. the length PQ is (x+2) units, and the length of QA is (3x-14) units
From the given Q is the middle point, which cut the diagonal PA into 2 equal halves.
By the definition of rhombus, diagonals meet at right angles.
Implies that PQ = QA
x+2 = 3x - 14
x-3x=-14-2
-2x=-16
2x = 16
dividing by 2 on both sides, we will get,
<h3>∴ x=8</h3><h3>Since Q cuts the diagonal PA into 2 equal halves, since the diagonals of rhombus meet at right angles we can equate x+2 = 3x-14 to find the value of x.</h3>
The line segment 
( since x=8)
<h3>∴
units</h3>
group the 1st 2 terms and last 2 terms:
(Z63 -2z^2) + (9z-18)
factor out GCF:
z^2(z-2) + 9(z-2)
now factor the polynomial:
(z-2) (z^2+9)
The answer is -4,7
The denominator can't equal zero. Factor the denominator:
x^2 - 3x - 28=
(X - 7)(x + 4); next set each set of parentheses equal to 0;
x - 7 = 0; so x=7 is one value
x + 4 = 0; so x=-4 is the other
Remember, x = 7 and x= -4 make the denominator zero, which is a "restriction" because you can't divide by zero.
Answer: PEMDAS
8•2 = 16
16+3x = -7
-3 -3
16 + x = -10
-16 -16
X= -26
Step-by-step explanation:
