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Nutka1998 [239]
3 years ago
15

15 20 Need to reduce this fraction to the lowest terms

Mathematics
2 answers:
wlad13 [49]3 years ago
7 0

Answer:

3/4

Step-by-step explanation:

BTW...can i plz get brainliest???   pllzzzzzz

faltersainse [42]3 years ago
3 0

Answer:

3/4

Step-by-step explanation:

15/20-- both go into 5----3/4

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Select or &lt; &gt; = to correctly classify each inequality. <br> -2/3 ___ 2/3<br> 1.4___ 1.6
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Helpp plzzz I will mark brainliestttt
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it 152.3

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75/12=□/4=160/□what is the answer?<br><br><br><br><br>​
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Answer:

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4 0
3 years ago
A bathtub is draining at a constant rate. After 2 minutes, it holds 30 gallons of water. Three minutes later, it holds 12 gallon
aliya0001 [1]
Let x, represent the number of minutes and y represents the number of gallons of water in the tub, then the ordered pairs (2, 30) and (5, 12) satisfies the equation.

Therefore the equation is given by: (y - 30)/(x - 2) = (12 - 30)/(5 - 2)
(y - 30)/(x - 2) = -18/3 x = -6
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y = -6x + 42

Required equation is y + 6x = 42.
5 0
3 years ago
Find, correct to four decimal places, the length of the curve of intersection of the cylinder 16x2 + y2 = 16 and the plane x + y
Yuri [45]

Let the curve C be the intersection of the cylinder  



16x^2+y^2=16



and the plane



x+y+z=1



The projection of C on to the x-y plane is the ellipse



16x^2+y^2=16



To see clearly that this is an ellipse, le us divide through by 16, to get



\frac{x^2}{1}+ \frac{y^2}{16}=1



or  



\frac{x^2}{1^2}+ \frac{y^2}{4^2}=1,



We can write the following parametric equations,



x=cos(t), y=4sin(t)



for  



0\le t \le 2\pi



Since C lies on the plane,



x+y+z=1



it must satisfy its equation.



Let us make z the subject first,  



z=1-x-y



This implies that,



z=1-sin(t)-4cos(t)



We can now write the vector equation of C, to obtain,



r(t)=(cos(t),4sin(t),1-cos(t)-4sin(t))



The length of the curve of the intersection of the cylinder and the plane is now given by,



\int\limits^{2\pi}_0 {|r'(t)|} \, dt



But  



r'(t)=(-sin(t),4cos(t),sin(t)-4cos(t))



|r'(t)|=\sqrt{(-sin(t))^2+(4cos(t))^2+(sin(t)-4cos(t))}



\int\limits^{2\pi}_0 {\sqrt{2sin^2(t)+32cos(t)-8sin(t)cos(t)} }\, dt=24.08778184



Therefore the length of the curve of the intersection  intersection of the cylinder and the plane is 24.0878 units correct to four decimal places.

6 0
3 years ago
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