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2 years ago

How do I determine the number of solutions there are for this system of equations?2x+6y=5 x+3y=2

1 answer:

5 0

Take one of the equation and, 2X+6y=5 and x+3y=2, now take one of the equation and (-2) x+3y=2 then -2x-6y=-4 add the common factor with the other equation which would cross out both variable leaving 0=1

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Marta_Voda [28]

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Step-by-step explanation:

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3 years ago

A square has side length (x+5) units. What is it’s area

daser333 [38]

The area of square is $x^{2}+10 x+25$ square units

<h3><u>Solution:</u></h3>

Given that square has side length (x+5) units

To find: area of square

<em><u>The area of square is given as:</u></em>

$\text {Area of square }=\mathrm{a}^{2}$

Where "a" is the length of side

From question, length of each side "a" = x + 5 units

Substituting the value in above formula,

$\text {Area of square }=(x+5)^{2}$

${\text {Expanding }(x+5)^{2} \text { using the algebraic identity: }} \\\\ {(a+b)^{2}=a^{2}+2 a b+b^{2}}\end{array}$

$\begin{array}{l}{\text {Area of square }=x^{2}+2(x)(5)+5^{2}} \\\\ {\text {Area of square }=x^{2}+10 x+25}\end{array}$

Thus the area of square is $x^{2}+10 x+25$ square units

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3 years ago

Express 0.32 as a fraction

jok3333 [9.3K]

The answer is (32/100)-(8/25 )

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2 years ago

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Multiple choice plz help!! Thank u!

lord [1]

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2 years ago

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Shalnov [3]

Answer:

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Step-by-step explanation:

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2 years ago