3 years ago

How do I determine the number of solutions there are for this system of equations?2x+6y=5 x+3y=2

1 answer:

5 0

Take one of the equation and, 2X+6y=5 and x+3y=2, now take one of the equation and (-2) x+3y=2 then -2x-6y=-4 add the common factor with the other equation which would cross out both variable leaving 0=1

You might be interested in

Divide 300 in a ratio of 3/7

Talja [164]

in short, we simply divide the whole 300 by (3+7), to get in a 3:7 ratio, and then distribute accordingly.

$\bf 300\qquad 3:7\qquad \cfrac{3}{7}~\hspace{5em}\cfrac{3\cdot \frac{300}{3+7}}{7\cdot \frac{300}{3+7}}\implies \cfrac{3\cdot 30}{7\cdot 30}\implies \cfrac{90}{210}\implies 90:210$