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-BARSIC- [3]
3 years ago
12

18. Find the measure of each numbered angle.

Mathematics
1 answer:
DiKsa [7]3 years ago
7 0

Answer:

m∠1 = 50°, m∠2 = 90°, m∠3 = 40°, and m∠4 = 50°

Step-by-step explanation:

Angles on straight line are equal;

m \angle1 + 130 = 180

m \angle1= 180 - 130 \\ m \angle1= 50

Vertical angles are equal,

m \angle4=  m \angle \: 1= 50 \degree

Complementary angles add up to 90°.

m \angle3 + m \angle4  = 90 \degree \\ 40 + m \angle3 = 90 \degree. \\  m \angle3 = 90 \degree - 50 \degree \\ m \angle3 = 40 \degree

Angles on straight line adds up to 180°

m \angle1 + m \angle2 + m \angle3 = 180 \degree

40 + m \angle2 + 50 = 180 \\  m \angle2 = 180 - 50 - 40 = 90

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Answer:

<u>Problem 4:</u>  Option C, 32

<u>Problem 5:</u>  You need to have the 2 and the x combine.  Make the table 2x than 16.

<u>Problem 6:</u>  x = 17

<u>Problem 7:</u>  She drew a 2, x and an 16.  Instead you must have 2x and 16.  2x + 16 = 50

Step-by-step explanation:

<u>Problem 4</u>

2 + x + 16 = 50

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Answer:  Option C, 32

<u>Problem 5</u>

You need to have the 2 and the x combine.  Make the table 2x than 16.

Answer:  You need to have the 2 and the x combine.  Make the table 2x than 16.

<u>Problem 6</u>

2x + 16 - 16 = 50 - 16

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x = 17

Answer:  x = 17

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She drew a 2, x and an 16.  Instead you must have 2x and 16.  2x + 16 = 50

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4 0
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Rate = 0.035 per weeks

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An artist has completed 1/14 of a painting in 2 weeks.

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Since BC is parallel to DE, triangles ABC and ADE are similar. What are the lengths of the unknown sides? It would be a great he
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Answer: AC= 10 cm and CE= 5 cm


Step-by-step explanation:

In the given picture, Δ ADE is a right triangle

∴ By Pythagoras theorem,

AD^2+DE^2=AE^2\\\Rightarrow\ (8+4)^2+9^2=AE^2\\\Rightarrow\ AE^2=12^2+9^2\\\Rightarrow\ AE^2=144+81=225\\\Rightarrow\ AE=15\ cm

Since triangles ABC and ADE are similar and corresponding sides of similar triangles are proportional therefore,

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⇒CE=AE-AC

⇒CE=15-10=5 cm


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