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-BARSIC- [3]
3 years ago
12

18. Find the measure of each numbered angle.

Mathematics
1 answer:
DiKsa [7]3 years ago
7 0

Answer:

m∠1 = 50°, m∠2 = 90°, m∠3 = 40°, and m∠4 = 50°

Step-by-step explanation:

Angles on straight line are equal;

m \angle1 + 130 = 180

m \angle1= 180 - 130 \\ m \angle1= 50

Vertical angles are equal,

m \angle4=  m \angle \: 1= 50 \degree

Complementary angles add up to 90°.

m \angle3 + m \angle4  = 90 \degree \\ 40 + m \angle3 = 90 \degree. \\  m \angle3 = 90 \degree - 50 \degree \\ m \angle3 = 40 \degree

Angles on straight line adds up to 180°

m \angle1 + m \angle2 + m \angle3 = 180 \degree

40 + m \angle2 + 50 = 180 \\  m \angle2 = 180 - 50 - 40 = 90

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Verdich [7]

Answer:

35?

Step-by-step explanation:

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3 years ago
A rectangular parking lot has a length that is 5 yards greater than the width the area of the parking lot is 300 yd.² find the l
ArbitrLikvidat [17]

Answer:

width=5yd and length=10yd

Step-by-step explanation:

To solve this problem, you need to start by asking what you do and don't know (always where to start with word problems)

We know that Area (A) = Length (L) * Width (W)

You know Area (A) = 50 sq. yds.

You don't know anything about the width, so let's just say Width (W) = x

And you know that the length is 5 yds longer than the width, so L = W + 5yd and, since W = x, we can say L = x + 5yd

Now, we recall that A = L * W, and, since A = 50, we can say 50 sq yd = L * W.

Well, now just plug in. What does W equal and L equal?

From above we plug in and can say that 50 sq yd = x * (x + 5 yd).

Multiply it out and you get 50 = x^2 + 5x (removing units for a moment so they don't clutter the lines).

Now there are a number of ways to solve this. You can tell (because of the "x^2") that it is quadratic. So let's get it equal to zero:

0 = x^2 + 5x - 50

Now you can factor it, use your quadratic formula, or (if you hated yourself) do it as a completing the square problem. I'm going to factor.

I can see from going through a list in my head that the factors 10 and -5 multiply to -50 and add to 5, so I know that

0 = x^2 + 5x - 50 = (x + 10)(x - 5)

And so you know that x = -10 or 5.

Well, you know the parking lot cannot be -10 yd long. So we must say that W = x = 5, and, since L = W + 5, then L = 5+5 = 10. So your width is 5 yd and length is 10 yd.

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2 years ago
4^3-(84÷14)^2<br><br> Please help! Show work too! thank you!! &lt;3
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Answer:

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Step-by-step explanation:

4^{3}-(84\div14)^{2}

Calculate 4 to the power of 3 = 64

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Divide 84 by 14 = 6

64-6^{2}

Calculate 6 to the power 2 = 36

64-36

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Answer:

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Step-by-step explanation:

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