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alisha [4.7K]
3 years ago
9

Will there be more thaan one relay exchange between 2 consecutive tenths of a mile​

Mathematics
1 answer:
kondor19780726 [428]3 years ago
6 0

Yes there will be more than one

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Andy claims that his bird can do single-digit multiplication. He shows the bird 12 cards with simple multiplication problems tha
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I believe the answer is 6
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Help ASAP please like rn
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Answer:

8/35 is correct

Step-by-step explanation:

Just multiply the numerator by numerator and denominator by denominator, then simplify

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Order these objects from heaviest to lightest. (Note: 1 pound = 16 ounces, 1 kilogram ≈ 2.2 pounds ,and 1 Tom = 2,000 pounds) it
Leya [2.2K]

Answer:

Ordering of objects from heaviest to lightest are  ⇒ <u> school bus weight 9 tons, elephant 5,500 kilograms, horse 1,100 pounds and grand piano 15,840 ounces.</u>

Step-by-step explanation:

Given:

School bus weight = 9 tons.

Horse = 1,100 pounds.

Elephant = 5,500 kilograms.

Grand piano = 15,840 ounces.

Now, order these objects from heaviest to lightest.

So, we need to take a common unit to order the items:

Thus, we take pounds as a common unit.

16 ounces = 1 pound.

1 kilogram = 2.2 pounds.

1 ton = 2,000 pounds.

Then, we calculate the weight of all items in pounds:

School bus 9 tons  =9\times 2000=18000\ pounds.

Horse 1100 pounds  =1100\ pounds.

Elephant 5500 kilograms  =5500\times 2.2=12100\ pounds.

Grand piano 15840 ounces  =15840\div 16=990\ pounds

According to question:

Ordering from heaviest to lightest:

<em>School bus = 18000 pounds, elephant = 12100 pounds, horse = 1100 pounds and grand piano = 990 pounds.</em>

Therefore, ordering of objects from heaviest to lightest are  ⇒  school bus weight 9 tons, elephant 5,500 kilograms, horse 1,100 pounds and grand piano 15,840 ounces.

7 0
3 years ago
4 thousands ÷ 10 = ________hundreds ÷ 10 =
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The answer is 10,000,000
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3 years ago
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How do I work this out?
zvonat [6]

We have to determine the value of \sum _{m=9} ^{21} (5m+6)

= (5(9)+6) + (5(10)+6) +(5(11)+6) + .......... + (5(21)+6)

= 51+56+61+66+ ........ + 111

Since, the common difference is 5, hence this series is in arithmetic progression.

Sum of AP is given by the formula:

\frac{n}{2}[2a+(n-1)d]

Since, there are 13 terms.

= \frac{13}{2}[2(51)+(13-1)5]

= \frac{13}{2}[102+60]

= \frac{13}{2}[162]

= 13 \times 81

= 1053

Therefore, the sum of the series is 1053.

So, Option G is the correct answer.

8 0
2 years ago
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