Answer:
The t-critical value for 95% confidence interval is ±2.2621
Step-by-step explanation:
We are given the following information in the question:
Sample size, n = 10
Alpha, α = 0.05
We have to find the value of t-critical at 95% confidence interval.
Degree of freedom = n - 1 = 9
The t-critical value for 95% confidence interval is ±2.2621
Answer: Angle C = 51.5°
Step-by-step explanation:
The diagram of the triangle is shown in the attached photo.
we would apply the law of Cosines which is expressed as
c² = a² + b² - 2bcCosC
Where a,b and c are the length of each side of the triangle and C is the angle corresponding to c.
Therefore,
18² = 23² + 14² - 2(23 × 14)CosC
324 = 529 + 196 - 2(322)CosC
324 = 725 - 644CosC
644CosC = 725 - 324
644CosC = 401
CosC = 401/644
CosC = 0.623
C = Cos^- 1(0.623)
C = 51.5° to the nearest tenth
