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stepladder [879]

3 years ago

10

The line passes through point Q, located at (-1, 2), and point R, located at (1, -2). Which two points determine a line parallel

to line Q R ?

1 answer:

alexandr1967 [171]3 years ago

7 0

Answer:

i need a picture to see sorry

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PLEASE HELP ASAP! BRAINLIEST TO BEST/RIGHT ANSWER

Semenov [28]

= 9 * 10^5 * 3 * 10^10

= 27 * 10^5 * 10^10

= 27 * 10^15

= 2.7 * 10^16 - The best selection appears to be the first option.

Good luck :)

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4 years ago

Harry is a builder.

sergij07 [2.7K]

Answer:

£39.95

Step-by-step explanation:

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3 years ago

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Papessa [141]

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2 years ago

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James is using cement to make a new sidewalk and new steps.

Tasya [4]

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3 0

3 years ago

Find all degree solutions in the interval 0° ≤ θ < 360°. If rounding is necessary, round to the nearest tenth of a degree. Us

xenn [34]

Answer:

$\theta_{1} \approx 30.473^{\textdegree}$

$\theta_{2} \approx 120.473^{\textdegree}$

$\theta_{3} \approx 210.473^{\textdegree}$

$\theta_{4}\approx 300.473^{\textdegree}$

Step-by-step explanation:

The equation needs to be rearranged in terms of one trigonometric function:

$5\cdot \sin 2\theta - 9\cdot \cos 2\theta = 0$

$5\cdot \tan 2\theta - 9 = 0$

$5\cdot \tan 2\theta = 9$

$\tan 2\theta = \frac{9}{5}$

$\theta = \frac{1}{2}\cdot \tan^{-1} \left(\frac{9}{5} \right)$

The tangent function has positive values in the 1st and 3rd Quadrants. Then, the solutions are:

$\theta_{1} \approx 30.473^{\textdegree}$

$\theta_{2} \approx 120.473^{\textdegree}$

$\theta_{3} \approx 210.473^{\textdegree}$

$\theta_{4}\approx 300.473^{\textdegree}$

3 0

3 years ago