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Strike441 [17]
3 years ago
11

PLEASE HELP ME I DONT UNDERSTAND THIS AT ALL

Mathematics
1 answer:
Delicious77 [7]3 years ago
4 0
What do you not understand
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Area = 67.25<span>7 (67.3 if rounded)</span>
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1. Amy Lynn's Kitchen offers a breakfast
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G:10

Step-by-step explanation:

If I am wrong I'm sorry.

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Astrid is in charge of building a new fleet of ships. Each ship requires 40 tons of wood, and accommodates 300 sailors. She rece
Lady bird [3.3K]

Answer:

Astrid needs 280 tons of wood to build ships that can accommodate 2100 sailors

Step-by-step explanation:

Here, in this question, we want to know the amount of wood needed by Astrid to accommodate 2100 sailors.

From the question, we can see that 40 tons are needed to build a ship that can accommodate 300 sailors.

Now, we want to make a calculation for the amount of wood needed for 2100 sailors.

Let’s have it this way;

40 tons = 300 sailors

x tons = 2100 sailors

So mathematically,

x * 300 = 2100 * 40

x = (2100 * 40)/300

x = 280 tons of wood

We can see that 280 tons of wood are needed to build ships that can accommodate 2100 sailors

8 0
3 years ago
Which expressions are equivalent to 2^5.2^4? Check all that apply.
USPshnik [31]

Answer:

2^9

Step-by-step explanation:

2^5 \times 2^4

The law of exponents says that when the base is same in multiplication, add the exponents.

2^{5+4}

=2^9

The answer is 2 to the power of 9.

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A particular variety of watermelon weighs on average 22.4 pounds with a standard deviation of 1.36 pounds. Consider the sample m
daser333 [38]

Answer:

a) 22.4 pounds.

b) 0.17 pounds.

c) 0.0127 = 1.27% approximate probability the sample mean weight will be less than 22.02.

d) c = 22.62

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Average 22.4 pounds with a standard deviation of 1.36 pounds.

This means that \mu = 22.4, \sigma = 1.36

Consider the sample mean weight of 64 watermelons of this variety.

This means that n = 64, s = \frac{1.36}{\sqrt{64}} = 0.17

a. What is the expected value of the sample mean weight?

By the Central Limit Theorem, 22.4 pounds.

b. What is the standard deviation of the sample mean weight?

By the Central Limit Theorem, 0.17 pounds.

c. What is the approximate probability the sample mean weight will be less than 22.02?

This is the p-value of Z when X = 22.02. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{22.02 - 22.4}{0.17}

Z = -2.235

Z = -2.235 has a p-value of 0.0127.

0.0127 = 1.27% approximate probability the sample mean weight will be less than 22.02.

d. What is the value c such that the approximate probability the sample mean will be less than c is 0.9?

This is the 90th percentile, that is, X = c when z has a p-value of 0.9, so X when Z = 1.28.

Z = \frac{X - \mu}{s}

1.28 = \frac{c - 22.4}{0.17}

c - 22.4 = 1.28*0.17

c = 22.62

4 0
3 years ago
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