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kolezko [41]
3 years ago
11

The process of deciding whether to do or use one additional unit of a resource.

Mathematics
1 answer:
LuckyWell [14K]3 years ago
8 0

Answer:

The answer to your question would be Thinking at the Margin.

Cheers!

Step-by-step explanation:


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What is the domain of the function y=3 In x graphed below?​
8_murik_8 [283]

Answer:

x>0

Step-by-step explanation:

points exist on the right of the graph so the domain is x>0

4 0
1 year ago
What is the answer?please help me
Maslowich

Answer:

y = 2x - 1 Graph B

y = 2x + 2 Graph A

y = 2x - 5 Graph C

Step-by-step explanation:

y = mx + c

c is where the line intersect the Y axis.

<h2>Substitute x for 0:</h2>

y = 2x - 1

2 * 0 - 1 = -1.

This is graph B because it intersects at 0,-1.

y = 2x + 2

2 * 0 + 2 = 2

This is graph A because it intersects at 0,2.

y = 2x - 5

2 * 0 - 5 = -5

This is graph C because it intersects at 0,-5.

6 0
3 years ago
What's 86/8 in a mixed number
dsp73

Answer:

10 6/8 or 10 3/4

Step-by-step explanation:

Calculate out how many times the denominator goes into the numerator. To do that, divide 86 by 8 and keep only what is to the left of the decimal point:

86 / 8 = 10.7500 = 10

Multiply the answer from Step 1 by the denominator and deduct that from the original numerator.

86 - (8 x 10) = 6

Keep the original denominator and use the answers from Step 1 and Step 2 to get this:

10 6/8

Minimize the fraction part from Step 3 by dividing the numerator and denominator by 2, which is the greatest common factor, to get the final answer. 86/8 as a Mixed Number is:

10 3/4

3 0
3 years ago
Simplify the expression:<br><br> 5x + 8 – 13y – 4x – 18 + 16y
aleksandrvk [35]

\text{Hey there!}

\text{Simply the equation: 5x + 8 - 13y - 4x - 18 + 16y}

\text{First you have to combine the \bf{like-terms}}

\text{5x-4x = 1x}

\text{-13y + 16y = 3y}

\text{8 + (-18) = -10}

\boxed{\boxed{\bf{Answer: 1x + 3y - 10}}}\checkmark

~\frak{LoveYourselfFirst:)}

4 0
3 years ago
Identify the surface with the given vector equation. r(u, v) = 2 sin(u) i + 5 cos(u) j + v k, 0 ≤ v ≤ 5 plane hyperbolic parabol
olchik [2.2K]
Note that this just produces three parametric equations:

x(u) = 2 \sin(u)
y(u) = 5 \cos(u)
z(v) = v

In the x-y plane, this is just he parametric equation for an ellipse (as a function of u). The z is simply a linear function. 

The surface is then an ellipse extruded along the z-axis. We get a elliptic cylinder.
6 0
3 years ago
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