Two boats leave a port at the same time, one going north and the other traveling south. The northbound boat travels 18 mph fast
1 answer:
Answer:
10 hours
Step-by-step explanation:
Two boats leave a port at the same time, one going north and the other traveling south.
<u>Southbound boat rate</u> = 40 mph
The northbound boat travels 18 mph faster than the southbound boat.
<u>Northbound boat rate</u> = 40 + 18 = 58 mph
Two boats rate = 40 + 58 = 98 mph (this means they are apart 98 km after one hour)
Total distance = 980 miles
Total rate = 98 mph
Time hours
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Answer:
(3) 49
Step-by-step explanation:
The circle diagram is attached below. angle mVS = 146°
and angle mST = 64°.
mWT = 360 -64 - 146 = 150 (angle at a point)
∠ VWS = 73° = mVS / 2
MVW = 180 - 146 = 34 (angle in a straight line)
MVW = 180 -73 - 34 = 73° (angle in a triangle)
∠TMR = 180 - 64 = 116° (angle on a straight line)
∠VMT = 116 + 34 = 150°
∠ MVT = ∠ MTV (base angles of an isosceles triangle)
150 +2∠ mTV = 180
∠ MTV = 15°
∠RVW = 73 - 15 = 58°
∠RVW + ∠ VWS + ∠VRW = 180
∠VRW = 180 - 58 - 73 = 49
