Answer: to find the mean add the numbers that were given then Divine by the amount of numbers you added. To find the median put all the numbers in numerical order and pick the middle one if it is an even amount of numbers than you pick the number exactly halfway between the two middle. To find the range you see how many numbers are repeated in which ever number is repeated the most amount of times that is the range.
Step-by-step explanation:
Answer: I don't know what you wanted to be solved, but, I solved for x
Step-by-step explanation:
<u>Solved for x</u>
- <u>x=(2\pm i\sqrt(6))/(2)</u>
Answer:
24 quarters and 49 nickels
Step-by-step explanation:
This situation has two unknowns - the total number of nickels and the total number of quarters. Because we have two unknowns, we will write a system of equations with two equations using the two unknowns.
- n+q=73 is an equation representing the total number of coins
- 0.05n+0.25q=8.45 is an equation representing the total value in money based on the number of coin. 0.05 and 0.25 come from the value of a nickel and quarter individually.
We write the first equation in terms of q by subtracting it across the equal sign to get n=73-q. We now substitute this for n in the second equation.
0.05(73-q)+0.25q=8.45
3.65-0.05q+0.25q=8.45
3.65+0.20q=8.45
After simplifying, we subtract 3.65 across and divide by the coefficient of q.
0.20q=4.8
q=24
We now know of the 73 coins that 24 are quarters. To find the number of nickels, we subtract 24 from 73 and get 49 nickels.
Answer:
the answer is the one you have selected
Step-by-step explanation:
Answer:
7
Step-by-step explanation:
Concept to Know: "A number is a perfect square if and only if it has odd number of positive divisors
"
Find all the squared values that lies between 360 and 630
360< 19², 20², 21², 22², 23², 24², 25² < 630
19², 20², 21², 22², 23², 24², and 25² are all the squared values that lies between 360 and 630. There are seven of those squared numbers so the answer is 7.
