First student has a 1 minute head start at .20 miles per minute.
This is a distance of .2 miles.
The second student has to make up this distance by running at .25 miles per minute. This produces a net gain on the first student by
(.25 -.20) = .05 miles per minute.
So how long does it take to run .20 miles at .05 miles per hour?
.2 miles / .05 miles per minute = 4 minutes.
Take out the greatest common factor, 9.
9(t-3)
Answer:
do five each day until you get to the last day youll have to do 10
Step-by-step explanation:
It would reflect over the x-axis and then reflect over the y-axis
Answer: X=5
y=10
Step-by-step explanation:
-9*x-6*y=15
║add
9*x-10*y=145
-------------------
-16*y=160
y=160/-16
y=-10
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-9*x-6*(-10)=15
-9*x+60=15
-9*x=-45
x=-45/-9
x=5