Ask question

Ask question

All categories

4 years ago

14

When designing a play area the mother created a scale drawing in which the side that measures 6 feet was represented by 3 inches

.What was the perimeter of the play area in the mothers scale drawing

1 answer:

Svetach [21]4 years ago

6 0

Answer:

12 inches

Step-by-step explanation:

if it is a square then you do 3×4 to get the perimeter

You might be interested in

How many 1/3 cup servings of juice are in a 5 cup container

vesna_86 [32]

Answer:

We can get 15 (1/3 cup) servings with a 5 cup container

Step-by-step explanation:

To solve this problem, we can easily divide 5 by (1/3) to find how many servings can be obtained

5 / (1/3)

= 5 / (0.3333)

= 15

This can be checked by adding together (1/3) fifteen times

(1/3) + (1/3)+ (1/3)+ (1/3)+ (1/3)+ (1/3)+ (1/3)+ (1/3)+ (1/3)+ (1/3)+ (1/3)+ (1/3)+ (1/3)+ (1/3)+ (1/3)

= 15/3 = 5

7 0

3 years ago

Please help fast will give brainliest

BaLLatris [955]

Answer:

b

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Oil-rich countries in the middle east cover about 4% of earth’s total land area but possess about 48% of the world’s known oil r

tiny-mole [99]

I'd say this high concentration is due to geological processes
Geological processes are things such as erosion, tectonic plate shifts, e.t.c.

8 0

4 years ago

What is the greatest common factor of the polynomial -25y^3+15y^2-5y

Sonbull [250]

Answer:

-5y

Step-by-step explanation:

4 0

3 years ago

find the volume of the solid formed by revolving the region bounded by the graphs of y = 4x - x^2 and f(x) = x^2 from [0,2] abou

Neko [114]

Answer:

$v = \frac{32\pi}{3}$

or

$v=33.52$

Step-by-step explanation:

Given

$f(x) = 4x - x^2$

$g(x) = x^2$

$[a,b] = [0,2]$

Required

The volume of the solid formed

Rotating about the x-axis.

Using the washer method to calculate the volume, we have:

$\int dv = \int\limit^b_a \pi(f(x)^2 - g(x)^2) dx$

Integrate

$v = \int\limit^b_a \pi(f(x)^2 - g(x)^2)\ dx$

$v = \pi \int\limit^b_a (f(x)^2 - g(x)^2)\ dx$

Substitute values for a, b, f(x) and g(x)

$v = \pi \int\limit^2_0 ((4x - x^2)^2 - (x^2)^2)\ dx$

Evaluate the exponents

$v = \pi \int\limit^2_0 (16x^2 - 4x^3 - 4x^3 + x^4 - x^4)\ dx$

Simplify like terms

$v = \pi \int\limit^2_0 (16x^2 - 8x^3 )\ dx$

Factor out 8

$v = 8\pi \int\limit^2_0 (2x^2 - x^3 )\ dx$

Integrate

$v = 8\pi [ \frac{2x^{2+1}}{2+1} - \frac{x^{3+1}}{3+1} ]|\limit^2_0$

$v = 8\pi [ \frac{2x^{3}}{3} - \frac{x^{4}}{4} ]|\limit^2_0$

Substitute 2 and 0 for x, respectively

$v = 8\pi ([ \frac{2*2^{3}}{3} - \frac{2^{4}}{4} ] - [ \frac{2*0^{3}}{3} - \frac{0^{4}}{4} ])$

$v = 8\pi ([ \frac{2*2^{3}}{3} - \frac{2^{4}}{4} ] - [ 0 - 0])$

$v = 8\pi [ \frac{2*2^{3}}{3} - \frac{2^{4}}{4} ]$

$v = 8\pi [ \frac{16}{3} - \frac{16}{4} ]$

Take LCM

$v = 8\pi [ \frac{16*4- 16 * 3}{12}]$

$v = 8\pi [ \frac{64- 48}{12}]$

$v = 8\pi * \frac{16}{12}$

Simplify

$v = 8\pi * \frac{4}{3}$

$v = \frac{32\pi}{3}$

or

$v=\frac{32}{3} * \frac{22}{7}$

$v=\frac{32*22}{3*7}$

$v=\frac{704}{21}$

$v=33.52$

8 0

3 years ago