Step-by-step explanation:
You have to do first and second derivatives :
y = a sin 3x + b cos 3x
dy/dx = 3a cos 3x - 3b sin 3x
d²y/dx² = - 9a sin 3x - 9b cos 3x
Next, you have to compare it :
let d²y/dx² = ky,
-9a sin 3x - 9b cos 3x = k(a sin 3x + b cos 3x)
-9(a sin 3x + b cos 3x) = k(a sin 3x + b cos 3x)
Therefore, k is equals to 9.
Answer: x=-5 and y=6
Step-by-step explanation: i hope i did it right tell if i didnt
Based on the calculations, we can logically deduce that the y-intercept of this sine function is equal to: A. 3.
<u>Given the following data:</u>
<h3>How to determine the y-intercept of this function?</h3>
Mathematically, a sine function is modeled by this equation:
y = Asin(ωt + ø)
<u>Where:</u>
- A represents the amplitude.
- ω represents angular velocity.
- ø represents the phase shift.
Also, the period of a sine wave is given by:
t = 2π/ω
2 = 2π/ω
ω = 2
Substituting the given parameters into the equation, we have;
y = 3sin(2t + π/2)
At t = 0, we have:
y = 3sin(2(0) + π/2)
y = 3sin(π/2)
y = 3sin(90)
y = 3 × 1
y = 3.
In conclusion, we can logically deduce that the y-intercept of this sine function is equal to 3.
Read more on phase shift here: brainly.com/question/27692212
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