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oksano4ka [1.4K]
3 years ago
9

Write the standard form of the line with the given information. Include your work in your final answer. Type your answer in the

box provided or use the upload option to submit your solution. The line that contains a slope of and passes through the point (-2, -3).
Mathematics
2 answers:
earnstyle [38]3 years ago
4 0
I am going to show you the procedure with any slope (given that you did not write the value of the slope)

general slope value: m
generic point (x1,y1)

Formula: y - y1 = m (x -x1)

y - y1 = mx - mx1

y - mx - y1 + mx1 = 0

x1 = -2 , y1 = -3 =>

y - mx - (-3) + m(- 2) = 0

y - mx + (3 -2m) = 0

Now suppose a value for m. Lets say it is m = 5.

y - 5x + (3 - 2*5) = 0

y - 5x + (3 - 10) = 0

y - 5x + (-7) = 0 and that is the standard form if the slope is 5. Now you can do the same with any slope.
Molodets [167]3 years ago
4 0

I'm assuming you meant to write the slope is 1/2


slope is 1/2

so  using the equation y-y₁=m(x-x₁)

Now don't forget that m= slope

so in our given points y₁ is the second number -3

x₁ is the first number -2.

now put it all together in their places.

<h2>y + 3 = 1/2 ( x + 2 )</h2>
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The correct answer is C) (5m^50 - 11n^8) (5m^50 + 11n^8)

We can tell this because of the rule regarding factoring the difference of two perfect squares. When we have two squares being multiplied, we can use the following rule.

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