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oksano4ka [1.4K]
3 years ago
9

Write the standard form of the line with the given information. Include your work in your final answer. Type your answer in the

box provided or use the upload option to submit your solution. The line that contains a slope of and passes through the point (-2, -3).
Mathematics
2 answers:
earnstyle [38]3 years ago
4 0
I am going to show you the procedure with any slope (given that you did not write the value of the slope)

general slope value: m
generic point (x1,y1)

Formula: y - y1 = m (x -x1)

y - y1 = mx - mx1

y - mx - y1 + mx1 = 0

x1 = -2 , y1 = -3 =>

y - mx - (-3) + m(- 2) = 0

y - mx + (3 -2m) = 0

Now suppose a value for m. Lets say it is m = 5.

y - 5x + (3 - 2*5) = 0

y - 5x + (3 - 10) = 0

y - 5x + (-7) = 0 and that is the standard form if the slope is 5. Now you can do the same with any slope.
Molodets [167]3 years ago
4 0

I'm assuming you meant to write the slope is 1/2


slope is 1/2

so  using the equation y-y₁=m(x-x₁)

Now don't forget that m= slope

so in our given points y₁ is the second number -3

x₁ is the first number -2.

now put it all together in their places.

<h2>y + 3 = 1/2 ( x + 2 )</h2>
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A quantity with an initial value of 600 decays exponentially at a rate of
Snowcat [4.5K]

Answer:

The value of the quantity after 87 months will be of 599.64.

Step-by-step explanation:

A quantity with an initial value of 600 decays exponentially at a rate of 0.05% every 6 years.

This means that the quantity, after t periods of 6 years, is given by:

Q(t) = 600(1 - 0.0005)^{t}

What is the value of the quantity after 87 months, to the nearest hundredth?

6 years = 6*12 = 72 months

So 87 months is 87/72 = 1.2083 periods of 6 years. So we have to find Q(1.2083).

Q(t) = 600(1 - 0.0005)^{t}

Q(1.2083) = 600(1 - 0.0005)^{1.2083} = 599.64

The value of the quantity after 87 months will be of 599.64.

8 0
3 years ago
A set of equations is given below:
nexus9112 [7]

I would think this is many solutions, the reason is because, there is no specific answer (y) so, x could be anything because it would have to equal to y, which could also be anything! I hope im right! Sorry if im wrong!

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3 years ago
Which pair of numbers is relatively prime? A. 42 and 77 B. 34 and 55 C. 45 and 102 D. 99 and 123
leonid [27]

Two pair of numbers are said to be relatively prime if there is no integer greater than 1, that divides them both.

Consider the given pair of the numbers to identify which pair is relatively prime.

1. Consider 42 and 77

7 is the number which divides 42 and 77 both. Therefore, they are not relatively prime.

2. Consider 34 and 55

Since, there is no number greater than 1, which divides both the numbers. So, they are relatively prime numbers.

3. Consider 45 and 102

3 is the number divides 45 and 102 both. Therefore, they are not relatively prime.

4.  Consider 99 and 123

3 is the number divides 99 and 123 both. Therefore, they are not relatively prime.

Therefore, Option B is the correct answer.

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How many pairs of triangles appear congruent? The triangles may overlap
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We will need an image but i am happy to change my answer with the correct answer as soon as we have what we need

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K is equal to l<br> m is equal to n<br> as the angles are marked, what's x and y
Greeley [361]
X - y + x + y = 180
2x = 180
  x = 90
2x - 2y = x + y
  x = 3y
  y = x/3
  y = 90/3
  y = 30

x - y = 90 - 30 = 60
x + y = 90 + 30 = 120
2x - 2y = 180 - 60 = 120

3 0
3 years ago
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