Sorry I don’t no anything about school
Answer:
the thing is black for me pls retake
Step-by-step explanation:
Let x = the 1st number, and y = the 2nd number.
Equation 1: The second of two numbers is 4 times the first ==> y = 4x
Equation 2: Their sum is 50 ==> x + y = 50
Substitute y = 4x into Equation 2, you get
x + 4x = 50
5x = 50
x = 50 / 5 = 10
y = 4x = 4(10) = 40
Answer:
<em>y = 2x+6</em>
Step-by-step explanation:
Let the output value be y
Let the input value be x
the output of a function is 6 more than 2 times the input
2 times the input is expressed as 2x
6 more than 2 times the input is expressed as 2x + 6
Since the output of a function is 6 more than 2 times the input, we will equate y to the resulting equation to have;
y = 2x + 6
<em>Hence the required equation is y = 2x+6</em>
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The inverse function is g(x) = ![\frac{x + 10}{15}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%20%2B%2010%7D%7B15%7D%20%20)
You can find the inverse of any function by switching the g(x) value (or whatever the function value is labelled) and the x value. Then solve for the new g(x) value. The result will be your inverse function.
g(x) = 15x - 10 ---> Switch the g(x) and x
x = 15g(x) - 10 ---> Add 10 to both sides
x + 10 = 15g(x) ----> Divide both sides by 15.
= g(x) ----> Switch the order
g(x) = ![\frac{x + 10}{15}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%20%2B%2010%7D%7B15%7D%20%20)
And that would be your inverse function.