Answer:
y = -3/2x + 6
Step-by-step explanation:
Parallel lines have the same slope so slope is -3/2
Using (4,0)
y = mx + b
0 = -3/2(4) + b
0 = -6 + b
b = 6
so y = -3/2x + 6
X = - 1/2
In other way is x = -0.2 , x = -5^-1
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Answer:
1π
Step-by-step explanation:
suppose the radius of semicircle P is r,
then the radius of semicircle Q = (r+d)/2 ... d≤r
radius of semicircle R = (r-d)/2
area P = 1/2 (r)²π
area Q = 1/2 ((r+d)/2)² π = 1/8 (r² + 2rd + d²)π
area R = 1/2 ((r-d)/2)² π = 1/8 (r² - 2rd + d²)π
shaded area = P-Q-R = 1/2 r²π - 1/4 (r² + d²)π
= ((r² - d²)/4) * π
because there is no constant r value in the question and d value changes with the r change, when the vertical segment length equal the semicircle P radius (r), r=2 and d = 0
therefore the shaded area = ((2² -0²)/4)*π = 1π
Answer:
D) y=-1/2x+4
Step-by-step explanation:
D) y=-1/2x+4
In order to be parallel, it has to have the same slope (-1/2). Also, if you plug in (-2,5) for x and y, it does pass through those coordinates.