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ICE Princess25 [194]
3 years ago
12

PLS HELP! which graph is the function 3x + 2y = 8 with the given domain {-2,0,2,4}??

Mathematics
1 answer:
Romashka [77]3 years ago
7 0

Answer:

D

Step-by-step explanation:

Domain of the function 3x + 2y = 8 are the possible set of x-values represented as {-2, 0, 2, 4}.

To know which graph represents the above given function, find the range values of the function by plugging in each value of x into the equation, to find y.

For x = -2,

3(-2) + 2y = 8

-6 + 2y = 8

2y = 8 + 6

2y = 14

y = 14/2

y = 7

(-2, 7)

For x = 0,

3(0) + 2y = 8

0 + 2y = 8

2y = 8

y = 8/2

y = 4

(0, 4)

For x = 2,

3(2) + 2y = 8

6 + 2y = 8

2y = 8 - 6

2y = 2

y = 2/2

y = 1

(2, 1)

For x = 4,

3(4) + 2y = 8

12 + 2y = 8

2y = 8 - 12

2y = -4

y = -4/2

y = -2

(4, -2)

The graph which shows the following set of coordinates pairs calculated above, ((-2, 7), (0, 4), (2, 1), (4, -2)), is the graph of the function 3x + 2y = 8.

Thus, the graph in option D the shows the following calculated coordinate pairs. Therefore, graph D is the answer.

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Answer:

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Step-by-step explanation:

48/2 (9+3)

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7 0
3 years ago
Which expression is equivalent to 0.75a + 10b + a – 2b?
Veseljchak [2.6K]

Answer:

1.75a+8b

Step-by-step explanation:

Question = 0.75a + 10b + a - 2b

First collect like terms 0.75a + a + 10b - 2b

= 1.75a + 8b

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3 0
3 years ago
Read 2 more answers
6. Suppose that a fair coin is tossed 2 times, and the result of each toss (H or T) is recorded.
nekit [7.7K]

Answer:

a) S= {HH, HT, TH, TT}

b) P(X=0) = (2C0) (0.5)^0 (1-0.5)^{2-0}= 0.25

P(X=1) = (2C1) (0.5)^1 (1-0.5)^{2-1}= 0.5

P(X=2) = (2C2) (0.5)^2 (1-0.5)^{2-2}= 0.25

And we have the following table:

X     |     0   |     1   |      2

P(X) |  0.25 |  0.5 |  0.25

Step-by-step explanation:

Let's define first some notation

H= represent a head for the coin tossed

T= represent tails for the coin tossed

We are going to toss a coin 2 times so then the size of the sample size is 2^2 = 4

a. What is the sample space for this chance experiment?

The sampling space on this case is given by:

S= {HH, HT, TH, TT}

b. For this chance experiment, give the probability distribution for the random variable of the total number of heads observed.

The possible values for the number of heads are X=0,1,2. If we assume a fair coin then the probability of obtain heads is the same probability of obtain tails and we can find the distribution like this:

P(X=0) = (2C0) (0.5)^0 (1-0.5)^{2-0}= 0.25

P(X=1) = (2C1) (0.5)^1 (1-0.5)^{2-1}= 0.5

P(X=2) = (2C2) (0.5)^2 (1-0.5)^{2-2}= 0.25

And we have the following table:

X     |     0   |     1   |      2

P(X) |  0.25 |  0.5 |  0.25

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