Answer:
c
Step-by-step explanation:
The derivative of the function g(x) as given in the task content by virtue of the Fundamental theorem of calculus is; g'(x) = √2 ln(t) dt = 1.
<h3>What is the derivative of the function g(x) by virtue of the Fundamental theorem of calculus as given in the task content?</h3>
g(x) = Integral; √2 ln(t) dt (with the upper and lower limits e^x and 1 respectively).
Since, it follows from the Fundamental theorem of calculus that given an integral where;
Now, g(x) = Integral f(t) dt with limits a and x, it follows that the differential of g(x);
g'(x) = f(x).
Consequently, the function g'(x) which is to be evaluated in this scenario can be determined as:
g'(x) =
= 1
The derivative of the function g(x) as given in the task content by virtue of the Fundamental theorem of calculus is; g'(x) = √2 ln(t) dt = 1.
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<h3>
Answer:</h3>
<h3>C. In x = -7 </h3>
<h3>
Step-by-step explanation:</h3>
<h3>13 + Inx = 6</h3>
<h3>1. Subtract 13 from both sides</h3>
13 + Inx - 13 = 6 -13
<h3>2. Simplify </h3>
= In x = -7
<h3>Solution : </h3>
<h3>= In x = -7</h3>
Answer:
Translate the circles so they share a common center point, and dilate circle Y by a scale factor of 3.
Step-by-step explanation: