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RSB [31]
3 years ago
13

Help please!!!!!!!!!!

Mathematics
2 answers:
nevsk [136]3 years ago
3 0

<em>so</em><em> </em><em>6</em><em>0</em><em> </em><em>is</em><em> </em><em>the</em><em> </em><em>answer</em><em>.</em>

<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em> </em><em>.</em><em>.</em>

Dimas [21]3 years ago
3 0
60 jars! 12/9 is 1.333 and 45x1.333 is about 60
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Use the continuous compound interest formula to find the indicated value
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The expression rt can be used to find the distance traveled by an object that has an average speed of r overtime t. How many mil
nikitadnepr [17]

Answer:

d = 12.5 \frac{mi}{hr} *2.2 hr = 27.5 mi

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Step-by-step explanation:

For this problem we know that the distance traveled by an object is given by:

d = rt  (1)

Where d is the distance r the average speed and t the time.

From the info given we know that t = 2.2 hours and r= 12.5 \frac{mi}{hr}

And replacing into formula (1) we got:

d = 12.5 \frac{mi}{hr} *2.2 hr = 27.5 mi

So then after 2.2 hours with an average speed of 12.5 mi/hr the hot air ballon will travel 27.5 mi

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3 years ago
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Papessa [141]

Answer:

86.28 ft²

Step-by-step explanation:

The figure given consists of a rectangle and a semicircle.

The area of the figure = area of rectangle + area of semicircle

Area of rectangle = l*w

Where,

l = 10 ft

w = 8 ft

area = l*w = 10*8 = 80 ft^2

Area of semicircle:

Area of semicircle = ½ of area of a circle = ½(πr²)

Where,

π = 3.14

r = ½ of 8 = 4 ft

Area of semi-circle = ½(3.14*4) = 6.28 ft²

Area of the figure = area of rectangle + area of semi-circle = 80 + 6.28 = 86.28 ft² (nearest hundredth)

6 0
3 years ago
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